Answer:
loooooovvvv veeee ladybug and cat noir squad
Explanation:
Answer:8.28 km
Explanation:
Given
First it drifts
2.5 km
![r_1=2.5cos45 i+2.5sin45 j](https://tex.z-dn.net/?f=r_1%3D2.5cos45%20i%2B2.5sin45%20j)
Secondly it drifts
4.70 km
![r_{12}=4.7cos60 i-4.7sin60 j](https://tex.z-dn.net/?f=r_%7B12%7D%3D4.7cos60%20i-4.7sin60%20j)
After that it drifted along east direction 5.1 km
![r_{23}=5.1 i](https://tex.z-dn.net/?f=r_%7B23%7D%3D5.1%20i)
After that it drifts
7.2 km
![r_{34}=-7.2cos55 i-7.2sin55 j](https://tex.z-dn.net/?f=r_%7B34%7D%3D-7.2cos55%20i-7.2sin55%20j)
After that it drifts
2.8 km
![r_{54}=-2.8cos5 i+2.8sin5 j](https://tex.z-dn.net/?f=r_%7B54%7D%3D-2.8cos5%20i%2B2.8sin5%20j)
=
+![\left [ 2.5sin45-4.7sin60-7.2sin55+2.8sin5\right ]\hat{j}](https://tex.z-dn.net/?f=%5Cleft%20%5B%202.5sin45-4.7sin60-7.2sin55%2B2.8sin5%5Cright%20%5D%5Chat%7Bj%7D)
![r_{5O}=2.299\hat{i}-7.95\hat{j}](https://tex.z-dn.net/?f=r_%7B5O%7D%3D2.299%5Chat%7Bi%7D-7.95%5Chat%7Bj%7D)
![|r_{5O}|=8.28 km](https://tex.z-dn.net/?f=%7Cr_%7B5O%7D%7C%3D8.28%20km)
for direction
![tan\theta =\frac{7.95}{2.299}=3.4580](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7B7.95%7D%7B2.299%7D%3D3.4580)
south of east
To solve this problem it is necessary to apply the concept related to root mean square velocity, which can be expressed as
![v_{rms} = \sqrt{\frac{3RT}{n}}](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B3RT%7D%7Bn%7D%7D)
Where,
T = Temperature
R = Gas ideal constant
n = Number of moles in grams.
Our values are given as
![v_e =11.2km/s = 11200m/s](https://tex.z-dn.net/?f=v_e%20%3D11.2km%2Fs%20%3D%2011200m%2Fs)
The temperature is
![T = 30\°C = 30+273 = 303K](https://tex.z-dn.net/?f=T%20%3D%2030%5C%C2%B0C%20%3D%2030%2B273%20%3D%20303K)
Therefore the root mean square velocity would be
![v_{rms} = \sqrt{\frac{3(8.314)(303)}{0.002}}](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B3%288.314%29%28303%29%7D%7B0.002%7D%7D)
![v_{rms} = 1943.9m/s](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%201943.9m%2Fs)
The fraction of velocity then can be calculated between the escape velocity and the root mean square velocity
![\alpha = \frac{v_{rms}}{v_e}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7Bv_%7Brms%7D%7D%7Bv_e%7D)
![\alpha = \frac{1943.9}{11200}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1943.9%7D%7B11200%7D)
![\alpha = 0.1736](https://tex.z-dn.net/?f=%5Calpha%20%3D%200.1736)
Therefore the fraction of the scape velocity on the earth for molecula hydrogen is 0.1736
Answer:
If a runner exerts 350 J of work to generate 175 W of power, it took the runner 2 seconds to do the work.
Explanation:
Power is defined as the speed with which a job is done. In other words, power is a given amount of work done in a given unit of time. That is, it is the amount of work per unit of time that some object or system produces.
Its expression is:
![P=\frac{W}{t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D)
where:
- P: Power developed by the force doing the work. Its unit of measure in the International System is the Watt (W)
- W: Work. Its unit of measure in the International System is the Joule (J)
- t: Time during which the work is carried out. Its unit of measurement in the International System is the second (s).
In this case:
Replacing:
![175 W=\frac{350 J}{t}](https://tex.z-dn.net/?f=175%20W%3D%5Cfrac%7B350%20J%7D%7Bt%7D)
and solving you get:
![t=\frac{350 J}{175 W}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B350%20J%7D%7B175%20W%7D)
t= 2 s
<u><em>
If a runner exerts 350 J of work to generate 175 W of power, it took the runner 2 seconds to do the work.</em></u>
Answer:
It can cause pollution of water in lakes and rivers.
Explanation:
<em>H</em><em>O</em><em>P</em><em>E</em><em> </em><em>T</em><em>H</em><em>I</em><em>S</em><em> </em><em>H</em><em>E</em><em>L</em><em>P</em><em>S</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>H</em><em>A</em><em>V</em><em>E</em><em> </em><em>A</em><em> </em><em>N</em><em>I</em><em>C</em><em>E</em><em> </em><em>D</em><em>A</em><em>Y</em><em> </em><em><</em><em>3</em>