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hjlf
3 years ago
7

An open organ pipe 30 cm long and a closed organ pipe 23 cm long, both of same diameter , are each sounding its first overtone ,

and these are in unison. What is the end correction of these pipes?
Physics
1 answer:
cupoosta [38]3 years ago
8 0

First overtone of open organ pipe is given as

f_{1o} = \frac{v}{L_1 + 2e}

first overtone of closed organ pipe is given as

f_{1c} = \frac{3v}{4(L_2 + e)}

now they are in unison so we will have

\frac{v}{L_1 + 2e} = \frac{3v}{4(L_2 + e)}

\frac{1}{30 + 2e} = \frac{3}{4(23 + e)}

90 + 6e = 92 + 4e

e = 1 cm

so end correction of both pipes is e = 1 cm

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To analyze the motion of a body that is traveling along a curved path, to determine the body's acceleration, velocity, and posit
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To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as

R = 350ft

a_t = 1.1ft/s^2

PART A )

a_c = \frac{V^2}{R}

a_c = \frac{V^2}{350}

Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 5.25ft/s^2

a = \sqrt{a_t^2+a_r^2}

5.25 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

27.5625 = 1.21 + \frac{v^4}{122500}

v=42.3877ft/s

Now calculate the angular velocity of the motorcycle

v = r\omega

42.3877 = 350\omega

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Calculate the angular acceleration of the motorcycle

a_t = r\alpha

1.1 = 350\alpha

\alpha = 3.1428*10^{-3}rad/s^2

Calculate the time needed by the motorcycle to reach an acceleration of

5.25ft/s^2

\omega = \alpha t

0.1211 = 3.1428*10^{-3}t

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PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 6.75ft/s^2

a = \sqrt{a_t^2+a_r^2}

6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

45.5625 = 1.21 + \frac{v^4}{122500}

v=48.2796ft/s

PART C)

Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is 21.5ft/s

a_r = \frac{v^2}{R}

a_r = \frac{21.5^2}{350}

a_r =1.3207ft/s^2

Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is 21.5ft/s

a = \sqrt{a_t^2+a_r^2}

a = \sqrt{(1.1)^2+(1.3207)^2}

a = 1.7187ft/s^2

PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is 6.75ft/s^2

a = \sqrt{a_t^2+a_r^2}

6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

45.5625 = 1.21 + \frac{v^4}{122500}

v=48.2796ft/s

3 0
3 years ago
a large parallel plate capacitor has plate seperation of 1.00 cm and plate area of 314 cm^2. The capacitor is connected across a
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Answer:

W = -2.76\times 10^{-9}~J

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The work done on the capacitor is equal to the difference in potential energy stored in the capacitor in two different cases.

The potential energy is given by the following formula:

U = \frac{1}{2}CV^2

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U = \frac{1}{2}3.14\epsilon (20)^2 = 628\epsilon

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The permittivity of the air is very close to that of vacuum, which is 8.8 x 10^-12.

So, the difference in the potential energy is

W = U_2 - U_1 = \epsilon(314 - 628) = -314 \times 8.8 \times 10^{-12} = -2.76\times 10^{-9}~J

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The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is_____
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An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms
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An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms voltage across the alternating source is 442 v.  The rms current will be  8.54 A

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RMS or root mean square current/voltage of the alternating current/voltage represents the D.C current/voltage that dissipates the same amount of power as the average power dissipated by the alternating current/voltage. For sinusoidal oscillations, the RMS value equals peak value divided by the square root of 2.

I (RMS) = RMS voltage / \sqrt{R^{2}+ X_{L} { ^{2}  }

           =  442 / \sqrt{29.4^{2} + 42.6^{2}  }

           = 442 / \sqrt{864.36 + 1814.76}

           = 442 / \sqrt{2679.12}

           = 8.54 A

To learn more about Alternating Current here

brainly.com/question/11673552

#SPJ4

6 0
1 year ago
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