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olya-2409 [2.1K]
3 years ago
9

CAT NOIR YAHHHHHHHHHHHHH

Physics
2 answers:
alisha [4.7K]3 years ago
7 0

Answer:

free points??????????

Brums [2.3K]3 years ago
4 0

Answer:

loooooovvvv veeee ladybug and cat noir squad

Explanation:

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Which of the following is equal to impulse?<br> A. Ft<br> B. m/s<br> C. pt<br> D. mv
tankabanditka [31]
Answer: A (Ft)

Explanation: The impulse experienced by the object equals the change in momentum of the object. In equation form, F • t = m • Δ v
5 0
3 years ago
A car traveling on a straight road at 15.0 meters per second accelerates uniformly to a speed of 21.0 meters per second in 12.0
oksano4ka [1.4K]
<h2>Option 3,  216 m is the correct answer.</h2>

Explanation:

We have initial velocity, u = 15 m/s

Time, t = 12 seconds

Final velocity, v = 21 m/s

We have equation of motion v = u + at

Substituting

                     21 = 15 + a x 12

                       a = 0.5 m/s²

Now we have equation of motion v² = u² + 2as

                           21² = 15² + 2 x 0.5 x s

                            s = 216 m

       Displacement = 216 m

Option 3,  216 m is the correct answer.

8 0
4 years ago
A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 poin
Musya8 [376]

Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude <em>y</em> at time <em>t</em> is

y(t)=50\,\mathrm m-\dfrac12gt^2

where <em>g</em> = 9.80 m/s^2 is the acceleration due to gravity.

The ball hits the ground when <em>y</em> = 0:

0 = 50\,\mathrm m-\dfrac12gt^2

t^2=\dfrac{100\,\mathrm m}g

t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}

6 0
4 years ago
You place a solid cylinder of mass M on a ramp that is inclined at an angle β to the horizontal. The coefficient of static frict
zlopas [31]

Answer:

Explanation:

Let the frictional force required be f .

frictional force is responsible in creating rotational motion in the cylinder.

torque created by frictional force = f R

if angular acceleration be α

α = f R / I , I is moment of inertia of cylinder .

α = a / R , a is linear acceleration.

f R / I = a / R

a = f R² / I

linear acceleration a of cylinder down the slope

ma = mgsinθ - f  , ( f force is acting upwards and mgsinθ is acting downwards )

mf R² / I = mgsinθ -f

f ( m R² / I + 1) = mgsinθ

f = mgsinθ / ( m R² / I + 1)

= mgsinθ / ( m R² / mk² + 1) , k is radius of gyration of cylinder.

= mgsinθ / (  R² / k² + 1)

Putting the given values

f = Mgsinβ /(  R² / k² + 1)

for cylinder ,  R² / k² = 2

f =  Mgsinβ /3

6 0
4 years ago
child mass 25kg moves with speed of 1.5m/s when 7.8 from the central of merry-go round. calculate the centripetal acceleration o
MAVERICK [17]

Answer:

0.2885 m/s²

Explanation:

The formula for centripetal acceleration is given as;

a_c=v^2/r

Given that;

speed = v = 1.5m/s

radius = r = 7.8

a_c=v^2/r\\\\\\a_c=1.5^2/7.8\\\\\\a_c=0.2885m/s^{2}

8 0
3 years ago
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