Answer:
b. nose, pharynx, larynx, trachea, bronchi, lungs
Explanation:
Answer:
K = 25351. 69 N / m
Explanation:
Given : Fk = 515 N , v = 1.8 m /s , d = 5.0 m , β = 22.0 ° , m = 150 kg
Using the work done by all forces at initial and the end can determine the constant of the spring
Ws + We - Fk = Em - Ef
- ¹/₂ * K * x² + m*g*h - F*d = 0 - ¹/₂ * m * v²
Also the round motion part
K* x = F + We
K * x = F + m*g*h
Replacing numeric to equal the equations and find the constant
¹/₂ * K * x² = 150*9.8* 5* sin (22°) - 5150* 5 + ¹/₂*150*(1.8m/s)²
K * x² = 421.358
Now use the other equation
K * x = 515 + 150*9.8* sin(22°)
K * x = 3268.35
Both equation give x' as a
x = 0.1289 m now using in any equation can find K
K = 25351. 69 N / m
Answer:
They are temperature, atmospheric pressure, wind, humidity, precipitation, and cloudiness. Together, these components describe the weather at any given time.
The distance traveled by the particle at the given time interval is 0.28 m.
<h3>
Position of the particle at time, t = 0</h3>
The position of the particle at the given time is calculated as follows;
x = 2 sin2(t)
y = 2 cos2(t)
x(0) = 2 sin2(0) = 0
y(0) = 2 cos2(0) = 2(1) = 2
<h3>
Position of the particle at time, t = 4</h3>
x = 2 sin2(t)
y = 2 cos2(t)
x(4) = 2 sin2(4) = 0.28
y(4) = 2 cos2(4) = 2(1) = 1.98
<h3>Distance traveled by the particle at the given time interval</h3>
d = √[(x₄ - x₀)² + (y₄ - y₀)²]
d = √[(0.28 - 0)² + (1.98 - 2)²]
d = 0.28 m
Thus, the distance traveled by the particle at the given time interval is 0.28 m.
Learn more about distance here: brainly.com/question/23848540
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