t = 2/3. Multiply the numbers in the parentheses by -1. It becomes 9t + -3t + -3 = 1. Combine like terms to get 6t + -3 = 1. Add 3 to both sides to get 6t = 4. Divide both sides by 6. t = 2/3
Centroid, orthocenter, circumcenter, and incenter are the four locations that commonly concur.
<h3>Explain about the concurrency of medians?</h3>
A segment whose ends are the triangle's vertex and the middle of the other side is called a median of a triangle. A triangle's three medians are parallel to one another. The centroid, also known as the point of concurrency, is always located inside the triangle.
The incenter of a triangle is the location where the three angle bisectors meet. The only point that can be inscribed into the triangle is the center of the circle, which is thus equally distant from each of the triangle's three sides.
Draw the medians BE, CF, and their intersection at point G in the triangle ABC. Create a line from points A through G that crosses BC at point D. We must demonstrate that AD is a median and that medians are contemporaneous at G since AD bisects BC (the centroid)
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Answer:
Yes
Step-by-step explanation:
y=x+6 is the slope. (1,7) is 2 right and 2 up from (3,9)
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
