Question

According to the 2000 U.S. Census Bureau, 49.65% of Texas residents were male. If one Texan was selected at random in 2000, what is the probability she was female? a. 0.4965 b. 0.5 c. 0.5035 d. 49

Answer 1

You subtract 49.65 from 100 to get the percentage of women, which comes to 50.35, and if you turn that into a probability you get .5035.

So the answer's c... hope this helps

Answer 2

Answer: 0.5035

Step-by-step explanation:

Given: According to the 2000 U.S. Census Bureau, 49.65% of Texas residents were male.

Thus the percent of male in Texas = $\frac{\text{Male}}{\text{Total}}\times100$=49.65%

When we divide percent by 100, we get the fraction of male to the total population=0.4965

⇒  If one Texan was selected at random in 2000, what is the probability she was male P(M)=0.4965

Since, there are only two events according to gender (Male and Female)

∴ P(M)+P(F)=1

⇒ P(F)=1-P(M)

⇒ P(F)=1-0.4965

⇒ P(F)=0.5035

Hence, If one Texan was selected at random in 2000, the probability she was female =0.5035