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3 years ago

Which of the following is an example of maintaining homeostasis?

Physics

2 answers:

UNO [17]3 years ago

7 0

Answer:

the first answer is correct

kompoz [17]3 years ago

4 0

It is 1 drinking water, because homeostasis is
the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.

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what type of boundary occurs where two plates move together causing one plae to descend in the mantle beneath the other plate

irinina [24]

This is called a subduction zone. The two plates converge, but one is forced under the other.

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4 years ago

Read 2 more answers

Write any two difference between CGS and MKS system of measurement ?

Tresset [83]

Answer:

MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.

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3 years ago

1. A 1000-kg car moves as speed from 10 m/s to 30 m/s in 20 seconds. What is the average speed? What is the acceleration? What i

kaheart [24]

Explanation:

Given parameters:

Mass of car = 1000kg

initial speed = 10m/s

final speed = 30m/s

time taken = 20s

For centripetal force:

velocity = 5m/s

radius = 30m

Unknown:

Average speed = ?

Acceleration = ?

Average force = ?

Centripetal force = ?

Solution:

Average speed is the rate of change of distance with time.

In this problem, we were given two speeds and we will simply just find their average. We sum them up and divide by 2

Average speed = $\frac{initial speed + final speed }{2}$

Average speed = $\frac{10 + 30}{2}$ = 20m/s

Acceleration is the change in the velocity or speed of a body with time.

Acceleration = $\frac{final speed - initial speed }{time}$

Acceleration = $\frac{30 - 10}{20}$ = 1m/s²

Average force on the car is the product of its mass and acceleration:

Acceleration = mass x acceleration

Acceleration = 1000 x 1 = 1000N

Centripetal force is the inward pull when a body moves round a fixed center.

It is given as:

F = $\frac{mv^{2} }{r}$

m is the mass of the body

v is the velocity

r is the radius

input the parameters:

F = $\frac{1000 x 5^{2} }{30}$ = 833.3N

learn more:

Acceleration brainly.com/question/11025333

Motion brainly.com/question/2863017

#learnwithBrainly

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4 years ago

The diagram shows the electric field near conducting sphere a which of the following statements is correct

Ludmilka [50]

I really don’t know but I hope this helps

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3 years ago

Coherent light of wavelength 525 nm passes through two thin slits that are 4.15Ã—10^(âˆ’2) mm apart and then falls on a screen 7

IRINA_888 [86]

A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

$sin \theta=\frac{n \lambda}{d}$

where

n is the order of the maximum

$\lambda$ is the wavelength

$a$ is the distance between the slits

In this problem,

n = 5

$\lambda=525 nm =5.25\cdot 10^{-7} m$

$a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m$

So we find

$\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}$

And given the distance of the screen from the slits,

$D=75.0 cm = 0.75 m$

The distance of the 5th bright fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 3.62^{\circ}=0.047 m = 4.7 cm$

B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

$sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}$

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

$\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}$

And the distance of the 8th dark fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm$

5 0

3 years ago