According to Newton's first law, a moving odject acted on by a net force of zero-

The takeoff speed for an airbus a320 jetliner is 82 m/s . velocity data measured during takeoff are as follows: t(s) vx(m/s) 0 0

bulgar [2K]

The table is:

t(s) vx(m/s)

0 0

10 23

20 46

30 69

a) from the data in the table, we observe that the acceleration is constant (because the rate of change in velocity is the same for each time interval of 10 seconds), so we can choose just one interval and calculate the acceleration as the ratio between the change in velocity and the change in time. Taking the first interval, we find

$a=\frac{\Delta v_x}{\Delta t}=\frac{23 m/s-0}{10s -0}=2.3 m/s^2$

b) To find the jet's acceleration in g's, we just need to divide the acceleration in m/s^2 by the value of g, the acceleration of gravity (9.81 m/s^2), so we find

$a_g=\frac{a}{g}=\frac{2.3 m/s^2}{9.8 m/s^2}=0.23 g$

c) the wheels leave the ground when the jet reaches its take-off velocity, which is 82 m/s.

At t=0s, the velocity of the jet is 0. We know that the acceleration is constant (a=2.3 m/s^2), so we can find the time t at which the jet reaches a velocity vf=82 m/s by using the equation

$v_f = v_i +at$

Re-arranging and substituting numbers, we find

$t=\frac{v_f}{a}=\frac{82 m/s}{2.3 m/s^2}=35.65 s$

6 0

3 years ago

Think about what subsequently happens to the ketchup, which is initially at rest, and use newton's first law to explain why this

Vika [28.1K]

Newton's first law of ketchup is if the bottle of ketchup is smacked upward, the contents (the ketchup) will tend to remain in place, and it will be closer to the opening in the bottle.

<h3>Further explanation </h3>

If we are trying to get ketchup out of the bottle, the best way to do it is to turn the bottle upside down and give the bottle a upward smack which force the bottle rapidly upward.

Newton first law said that every object tries to continue in its state of rest or uniform motion unless an external force acted upon it (In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force). Newton first law describe the relationship between a body and the forces acting upon it, and its motion in response to those forces.

Inertia explained by Sir Isaac Newton in his first law of motion (Newton law of motion). The law states that an object at rest stays at rest and an object continues its state of motion until an external force acts on it. The examples are one's body movement to the side when a car makes a sharp turn

<h3>Learn more</h3>

Learn more about newton's first law https://brainly.in/question/4978079

<h3>Answer details</h3>

Grade: 9

Subject: physics

Chapter: newton's first law

Keywords: newton's first law

7 0

2 years ago

Read 2 more answers

How much heat is required to vaporize 1.5kg of liquid water at its boiling point

Dafna11 [192]

Given:

Water, 1.5kg at boiling point

Required:

Heat required to vaporize at boiling point

Solution:

Water at boiling point is at 100degrees Celsius

Changing it into Kelvin, just dd 273 to 100 = 373 K

H = mCpT

H = (1.5kg)(4.184kJ/kg-K)(373K)

3 0

3 years ago

An engineer wishes to design a roller coaster so that

nataly862011 [7]

To prevent cars from falling, the radius at the top of the circle should be

small such cars inverted at the top remain attached during motion.

Correct response;

The radius of the coaster can be <u>C) 20 m</u>

<h3>Method by which the above option is selected</h3>

Mass of roller coaster car, m = 500 kg

Speed at the top of the circle, v = 20 m/s

Required:

The maximum radius of the circular path the roller coaster car.

Solution:

$\displaystyle Centrifugal \ force, \, F_{c} = \mathbf{\frac{m \cdot v^2}{r}}$

Where;

r = The radius of the circular path.

Weight of the roller coaster car = m·g = The centripetal force

Where;

g = Acceleration due to gravity = 9.81 m/s²

At equilibrium, we have;

Centrifugal force = Centripetal force

$\displaystyle \frac{m \cdot v^2}{r} = \mathbf{ m \cdot g}$

Therefore;

$\displaystyle r = \mathbf{ \frac{v^2}{g}}$

Which gives;

$\displaystyle r = \frac{20^2}{9.81} \approx 40.77$

The maximum radius for safety of a roller coaster, r ≈ 40.77 meters

$\displaystyle Range \ of \ radius \ of \ the \ circle = \frac{40.77}{4} \leq Radius \ of \ circle \leq 40.77$

Which gives;

Range of the radius of the circle = 10.2 ≤ Radius of circle ≤ 40.77

The correct option for safety considerations is therefore;

<u>C) 20 m</u>

<em>The possible question options are;</em>

Learn more about centripetal force here:

brainly.com/question/12674230

7 0

2 years ago

What is the difference between reflection and refraction? What changes and what does not change.

wolverine [178]

Answer:

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

Explanation:

8 0

1 year ago