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zheka24 [161]
3 years ago
13

What are 5 aspects of resistors that are connected in parallel ?

Physics
1 answer:
amid [387]3 years ago
6 0

Answer:

Voltage.

current.

Resistance.

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You are in space watching the two astronauts at rest in your frame of reference. They have identical mass, connected by a 12-m l
VARVARA [1.3K]

Answer:

4 m

Explanation:

don't think so that's the answer

6 0
3 years ago
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz
asambeis [7]
By using the Plancks-Einstein equation, we can find the energy;
E = hf
where h is the plancks constant = 6.63 x 10⁻³⁴
f = frequency = 3.55 x 10¹⁷hz
E = (6.63 x 10⁻³⁴) x (3.55 x 10¹⁷)
E = 2.354 x 10⁻¹⁶J
3 0
3 years ago
What is the first step of the STOP procedure for assessing acute sports injuries?
Troyanec [42]
The first step of the STOP procedure is S, which stands for "stop." This indicates that you should stop what you're doing to place your full attention on the situation at hand. This will allow you to stay focused on what's specifically happened to an athlete. 
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3 years ago
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Particles of m1 and m2 (m2>m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, bo
Tresset [83]

Answer:

The velocity with which the mass will hit the floor is v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.}

Explanation:

If the tension in the string is T, for m_1 we have

T- m_1g =m_1a,

and for the mass m_2

T -m_2g = -m_2a

From these equations we solve for a and get:

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

The kinematic equation

v_f^2 = v_0^2+2ax

gives the final velocity v_f of a particle, when its initial velocity was v_0, and has traveled a distance x while undergoing acceleration a.

In our case

v_0 = 0 (the initial velocity of the particles is zero)

a =(\dfrac{m_2-m_1}{m_2+m_1}) g.

which gives us

v_f^2 = 2ax

v_f^2 =2(\dfrac{m_2-m_1}{m_2+m_1}) g

\boxed{v_f = \sqrt{2(\dfrac{m_2-m_1}{m_2+m_1}) x.} }

which is the velocity with which the mass m_2 will hit the floor.

8 0
3 years ago
A sound wave travels twice as far in neon (Ne) as it does it krypton (Kr) in the same time interval. Both neon and krypton can b
avanturin [10]

Answer:

281.6 K

Explanation:

The speed of sound in an ideal gas is given by c = √(γKT/m).

From the question speed of sound in Ne, c₁ = 2c₂ speed of sound in Kr

c₁ = √(γKT₁/m₁) and c₂ = √(γKT₂/m₂)

So  √(γKT₁/m₁)  = 2√(γKT₂/m₂) where T₁, m₁ and T₂, m₂ are the temperatures and atomic masses of Neon and Krypton respectively.

So, √(T₁/m₁)  = 2√(T₂/m₂)

(T₁/m₁)  = 4(T₂/m₂) (squaring both sides)

T₁ = 4(T₂m₁/m₂)

Given that m₁ = 20.2 u , m₂ = 83.8 u, T₂ = 292 K

T₁ = 4(292 × 20.2/83.8) K = 23593.6/83.8 = 281.55 K ≅ 281.6 K

6 0
3 years ago
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