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3 years ago

Explain an example of how energy is transferred from one form to another

Physics

1 answer:

s2008m [1.1K]3 years ago

4 0

Answer:

Explanation:

Energy can can be transferred from one form to another in many ways,

Forms of energy that exist are Chemical Energy, Nuclear Energy

Electrical Energy Heat Energy and others.

one example is conversation of chemical energy by stove to heat energy.

Chemical energy which a form of energy that allow substance to experience chemical reaction, when a gasoline which posses chemical energy is put into stove then it convert this chemical energy to heat energy through burning which helps our food to cook as a result of heat energy gotten

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Can you see the equator from outer space??

DaniilM [7]

No, you can't see the equator.

4 0

3 years ago

On the return home, the cyclist accelerates from 2.0 m/s with a an acceleration of 2.2 m/s 2 . Calculate the time it takes the c

jonny [76]

motion

vt=vo+at

10 m/s = 2 m/s + 2.2 m/s².t

8 = 2.2t

$\tt t=\dfrac{8}{2.2}=3.63~s$

7 0

3 years ago

In a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 15 mm from the central bright spo

jeka94

Answer:

The distance from the central bright spot are $156.8\times10^{-3}\ mm$ and $142.9\times10^{-3}\ mm$ .

Explanation:

Given that,

Wavelength = 490 nm

Distance y= 15 mm

Length L=1.6 m

New wavelength = 670

We need to calculate the distance from the central bright spot

Using formula of distance

$y= \dfrac{m\lambda L}{d}$

$d=\dfrac{m\lambda L}{y}$

Put the value into the formula

$d=\dfrac{3\times490\times10^{-9}\times1.6}{15\times10^{-3}}$

$d=156.8\times10^{-6}\ m$

$d=156.8\times10^{-3}\ mm$

We need to calculate the distance from the central bright spot for new wavelength

Using formula of distance

$d=\dfrac{m\lambda L}{y}$

Put the value into the formula

$d=\dfrac{2\times670\times10^{-9}\times1.6}{15\times10^{-3}}$

$d=142.9\times10^{-6} m$

$d=142.9\times10^{-3}\ mm$

Hence, The distance from the central bright spot are $156.8\times10^{-3}\ mm$ and $142.9\times10^{-3}\ mm$ .

8 0

3 years ago

A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid

Sergeeva-Olga [200]

Answer:

$8.37*10^5$ rpm

Explanation:

Given that rotational kinetic energy = $4.66*10^9J$

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = $\frac{1}{2} mr ^2$

Rotational K.E is illustrated as $(K.E)_{rt} = \frac{1}{2} I \omega^2$

$\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }$

$\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }$

$\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }$

$\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }$

$\omega = 87636.04$

$\omega = 8.76*10^4 rad/s$

Since 1 rpm = $\frac{2 \pi}{60} rad/s$

$\omega = 8.76*10^4(\frac{60}{2 \pi})$

$\omega = 836518.38$

$\omega = 8.37 *10^5 rpm$

3 0

3 years ago

What is the energy stored in the 10.5 μ F 10.5 μF capacitor of a heart defibrillator charged to 8250 V ?

Kay [80]

Answer:

356.33 J

Explanation:

Energy: This can be defined as the ability or the capacity to do work. The S.I unit of Energy is Joules (J).

The Energy stored in a capacitor = 1/2CV²

E = 1/2CV².............................. Equation 1.

Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = potential difference across the plates of the capacitor.

Given: C = 10.5 μF = 10.5×10⁻⁶ F, V = 8250 V.

Substitute into equation 1

E = 1/2(10.5×10⁻⁶)(8250)²

E = 357.33 J.

Thus the energy stored in the defibrillator = 356.33 J

3 0

4 years ago