Ok, I think this is right but I am not sure:
Q = ϵ
0AE
A= π π
r^2
=(8.85x10^-12 C^2/Nm^2)
( π π (0.02m)^2)
(3x10^6 N/C) =3.3x10^-8 C = 33nC N = Q/e = (3.3x10^-8 C)/(1.60x10^-19 C/electron) = 2.1x10^11 electrons
Answer:
<em>1</em><em>. </em><em>A body is said to be at rest if its position does not change with respect to its surroundings.</em>
<span>3.2x10^-2 seconds (0.032 seconds)
This is a simple matter of division. I also suspect it's an exercise in scientific notation, so here is how you divide in scientific notation:
9.6 x 10^6 m / 3x10^8 m/s
First, divide the significands like you would normally.
9.6 / 3 = 3.2
And subtract the exponent. So
6 - 8 = -2
So the answer is 3.2 x 10^-2
And since the significand is less than 10 and at least 1, we don't need to normalize it.
So it takes 3.2x10^-2 seconds for the radio signal to reach the satellite.</span>
Answer:
7229 N
Explanation:
The gravitational force between the Death Star and the Millenium Falcon is given by:
where
is the gravitational constant
is the mass of the Death Star
is the mass of the Millennium Falcon
is the radius of the Death Star
Substituting numbers into the equation, we find the force
Answer:
1. 0.45 s.
2. 4.41 m/s
Explanation:
From the question given above, the following data were obtained:
Height (h) = 1 m
Time (t) =?
Velocity (v) =?
1. Determination of the time taken for the pencil to hit the floor.
Height (h) = 1 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
1 = ½ × 9.8 × t²
1 = 4.9 × t²
Divide both side by 4.8
t² = 1/4.9
Take the square root of both side
t = √(1/4.9)
t = 0.45 s.
Thus, it will take 0.45 s for the pencil to hit the floor.
2. Determination of the velocity with which the pencil hit the floor.
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 0.45 s.
Final velocity (v) =?
v = u + gt
v = 0 + (9.8 × 0.45)
v = 0 + 4.41
v = 4.41 m/s
Thus, the pencil hit the floor with a velocity of 4.41 m/s
