Answer:
B) (4,5)
Step-by-step explanation:
Hope this helps.. (again)
Answer: in order to qualify, the time must be at least 15.93 minutes
Step-by-step explanation:
Let x be a random variable representing the average response times of fire departments to fire calls. Since it follows a normal distribution, we will determine the z score by applying the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = population standard deviation
From the information given,
µ = 12.8 minutes
σ = 3.7 minutes
in order to qualify for the special safety award, the probability value would be to the right of the z score corresponding to 80%
The z score corresponding to 80% on the normal distribution table is 0.845
Therefore,
0.845 = (x - 12.8)/3.7
0.845 × 3.7 = x - 12.8
3.13 = x - 12.8
x = 12.8 + 3.13 = 15.93
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
In multiplication, a negative times a positive has a negative answer. if both are positive or both are negative, the answer is positive.
5 * -5 = -25
-5* -5 = 25
in divisions say you have
-5/5 = -1
-5/-5= 1
5/-5= -1
in addition and subtraction, subtracting a negative means to add the two numbers. adding a negative means to subtract the second number.
5+ (-5) = 0
5- (-5) = 10
Answer:
Step-by-step explanation:
Given
Required
Determine the solution
Since b is a perfect square, the equation can be expressed as:
Apply difference of two squares:
Split:
Remove brackets:
Make a the subject in both equations
The solution can be represented as:
