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loris [4]
3 years ago
10

What is the distance between R(5,2) and S(4,-7)? Round to the nearest tenth.

Mathematics
1 answer:
Naddik [55]3 years ago
5 0
You can calculate the distance between two point using this fomula: 

√(x_2-x_1)^2+(y_2-y_1)^2


If you insert you values you get:

 √(4-5)^2+(-7-2)^2 = 9.06 = 9.1
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3 years ago
PLS HELO THANK YOUUUUU
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2 years ago
the area of a square mirror is 256 inches squared. A Rectagular mirror has a width the same as the square mirror`s width.Its len
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3 years ago
9. Whats is the equivalent fraction for 0.625
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5/8

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6 0
3 years ago
Read 2 more answers
Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

6 0
3 years ago
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