You 1234 and yo will need to kondd
<em>12</em>
<em>Step by Step, Following the rules of Pemdas</em>
<em>22 - (3.1 + 4.4) + 2.5</em>
<em>22 - 7.5 + 2.5</em>
<em>22 - 10</em>
<em>12</em>
<em />
<em>-Ɽ3₮Ɽ0 Ⱬ3Ɽ0
</em>
<em>
</em>
<em />
Steps by explanation:
for second one
centroid ={(1+3+5)/3,(2+4+0)/3}=(9/3,6/3)
=(3,2)
Answer:
-17/9
Step-by-step explanation:
Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
