Question

Three consecutive even numbers are such that the sum of four times the smallest and twice the largest exceeds three times the second by 2006. What is the sum of the digits of the smallest number

Answer 1

Answer:

the sum of the digits of the smallest number 668 = 6+6+8 = 20

Step-by-step explanation:

3 consecutive even number: x, x+2, x+4

4x + 2*(x+4) = 3*(x+2) + 2006

6x + 8 = 3x + 6 + 2006 = 3x + 2012

6x - 3x = 2012 - 8 = 2004

3x = 2004

x = 668

the sum of the digits of the smallest number = 6+6+8 = 20