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3 years ago

What is the y intercept of the linear function graphed here

Mathematics

2 answers:

Ne4ueva [31]3 years ago

7 0

The y-intercept is (0,-1)

earnstyle [38]3 years ago

7 0

Answer:

0,-1

Step-by-step explanation:

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Round 1.7802 to 1 significant figure

tiny-mole [99]

Answer:

It would be 2

Step-by-step explanation:

Since they are looking for only 1 significant fig. you would round the number that would make this correct, for example:

You would look at 1.7 and ignore the others...

7 is greater than 5 so it'll affect the 1

And that how you get 2 : )

3 0

3 years ago

What is the value represented by letter A on the box plot of data? 50, 20, 40, 50, 50, 85

Juli2301 [7.4K]

Answer:

the answer to your question is 5

Step-by-step explanation:

7 0

3 years ago

Can anyone solve this 100+3-4(4-5) divided by 6+5+5+5+300

ioda

(100+3-4(4-5))/(6+5+5+5+300)
=(100+3-16+20)/(321)
=(107)/(321)
=1/3

Hope it helps : )

8 0

2 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

The sum of 3 consecutive integers is 90. Find the largest integer if x is the smallest integer.

____ [38]

Answer:

Step-by-step explanation:

x, x+1, x+2

x + x + 1 +x + 2 = 90

3x + 3 = 90

-3 -3

3x = 87

/3 /3

x = 29

29 + 2 = 31

3 0

3 years ago

What is the y intercept of the linear function graphed here​

What is the y intercept of the linear function graphed here