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san4es73 [151]
2 years ago
15

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0 gram setting. It

is believed that the machine is underfilling the bags. A 36 bag sample had a mean of 444.0 grams. A level of significance of 0.1 will be used. Determine the decision rule. Assume the standard deviation is known to be 22.0. Enter the decision rule.
Mathematics
1 answer:
MrRa [10]2 years ago
5 0

Answer:

|Z| = |-1.36| < 1.645 at 0.1 level of significance

The null hypothesis is accepted

A manufacturer of banana chips are filling machine works correctly at the mean 449

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of the Population(μ) = 449

The Standard deviation of the population(σ) = 22

size of the sample 'n' = 36

mean of the sample(x⁻) = 444

Given the level of significance(α) = 0.1

Critical value Z = 1.645

<u><em>Step(ii):</em></u>-

<em>Null hypothesis</em>:H₀:

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0

(μ) = 449

<em>Alternative Hypothesis</em>:H₁: (μ) ≠ 449

Test statistic

                  Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } } \\= \frac{444-449}{\frac{22}{\sqrt{36} } }

                 = -1.36

<em>Final answer:-</em>

|Z| = |-1.36| < 1.645 at 0.1 level of significance

The null hypothesis is accepted

A manufacturer of banana chips are filling machine works correctly at the mean 449

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