Need help plsss Question is below

mihalych1998 [28]

Answer:

X represents the number of product so 3 cause you have 2 pastas and 1 cheese. The length represents the total cost. I think 3 would represent cost? I'm not totally sure on that one. Hope this helps!

Step-by-step explanation:

7 0

2 years ago

Consider the function f(x) = 3.x2 + 7x + 2. what is the value of the discriminat?

Vika [28.1K]

Answer:

The Discriminant is 25

Step-by-step explanation:

For this case, the discriminant will be given by

b ^ 2 - 4 * a * c

Where

b = 7

a = 3

c = 2

substituting

b ^ 2 - 4 * a * c = (7) ^ 2 - 4 * (3) * (2) = 25

Therefore the value of the discriminant is 25.

How many x-intercepts does this function have?

It has two intercepts with the x axis and can be found by equaling the function to zero. That is to say,

3x2 + 7x + 2 = 0

The results will be the interceptions with x.

What are the number of zeros for this function?

The number of zeros for this function is

two real number solutions

Because it is a quadratic function.

3 0

3 years ago

Jerry ate 1,070 calories total at breakfast. He ate a cup of yogurt that had 150 calories in it and some granola. Each cup of gr

Maru [420]

Answer:

4 cups that's how many cups Jerry ate

4 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$