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4 years ago

11

A chef makes 3 containers of soup that fills a total of 120 soup bowls. Each container of soup coasts $30 to make. What is the c

oast per bowl for the soup

1 answer:

xxMikexx [17]4 years ago

4 0

Answer:

1.333333333.....$

Step-by-step explanation:

Container = C

Bowl = B

Question : Value of B ?

3C = 120 Bowls

C = 40 Bowls for 30$

B = $\frac{40}{30} = \frac{4}{3} = 1.3333..........$ $

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Can someone explain this, please?

Lostsunrise [7]

If you notice the terms, they're

7, -21, 63, -189 and so forth.

7*-3 = -21 and -21 * -3 is 63 and so forth, meaning the "common ratio" is -3.

now, for a common ratio say "r", which is a fraction, namely less than ±1 and more than 0, or |r| < 1 , you do have a convergent sequence.

however this one notice, |-3| is 3, and that's greater than 1 clearly, therefore is divergent, meaning the summation has no finite value.

6 0

3 years ago

Ellen planted 1/5 of her entire garden on Friday, 2/15 of her garden on Saturday, and 3/10 of the garden on Sunday. What fractio

xxMikexx [17]

Answer:

19/30

Step-by-step explanation:

1/5 + 2/15 + 3/10

We need the LCD of 5, 15, and 10.

LCD = 30

1/5 + 2/15 + 3/10 =

= 6/30 + 4/30 + 9/30

= 19/30

Answer: 19/30

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3 years ago

A soccer player is training during pre-season. His trainer tells him to

yulyashka [42]

Answer:

48,650

Step-by-step explanation:

3,475 times 14 bc thats how many days are in 2 weeks(obviously)

4 0

3 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

substitute the values

$BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units$

Step 3

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

therefore

<u>the answer is</u>

the length of BD is 11.93 units

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3 years ago

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