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Blababa [14]
3 years ago
15

Melting point is defined as

Chemistry
2 answers:
Ksenya-84 [330]3 years ago
7 0

Explanation:

The temperature which a given solid will melt

zavuch27 [327]3 years ago
7 0

Answer:

the temperature at which a given solid will melt.

Explanation:

I don't know how to Explain it. (lol)

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Calculate the molarity of a solution containing 0.875moles of glucose in 1.5kg of water.
stepladder [879]

molarity = moles of solute/liters of solution

We know the moles of solute: 0.875 moles of glucose. We can easily determine the liters of solution by using the mass of water given (1.5 kg) and the density of water (approximately 1 kg/L): they're, for all intents and purposes, equal (the approximation isn't large enough to be appreciable here, nor would the volume of the solution appreciably change since the solute is a solid that will <em>dissolve into </em>the solvent). So, we have 1.5 L of solution.

Now, we plug in what we have:

molarity = 0.875 moles of glucose/1.5 L of solution = 0.58 M glucose

The answer is provided to two significant figures since we're given the mass of water to two significant figures.

5 0
3 years ago
Automobile battery acid is 38% H2SO4 and has a destiny of 1.29g/ml. Calculate the molality and the molarity of this solution. ​
baherus [9]

Answer:

M=5.0M\\\\m=6.2m

Explanation:

Hello,

In this case, 38 % is commonly a by mass concentration, meaning that we have 38 grams of solute (sulfuric acid) per 100 grams of solution (water+sulfuric acid):

38\%=\frac{m_{H_2SO_4}}{m_{H_2SO_4}+m_{H_2O}}

Hence, we compute the moles of sulfuric acid in 38 grams by using its molar mass (98 g/mol):

n_{H_2SO_4}=38g*\frac{1mol}{98g}=0.39mol H_2SO_4

Next, the volume of the solution in litres by using the density of the solution:

V_{solution}=100g*\frac{1mL}{1.29g}*\frac{1L}{1000mL} =0.0775L

This is done since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in litres, thus we have:

M=\frac{n}{V}=\frac{0.38mol}{0.0775L}=5.0M

On the other hand, the molality is defined as the ratio of the moles of the solute to the mass of the solvent in kilograms, thus, we compute the mass of water (solvent) as shown below:

m_{H_2O}=100g-38g=62g*\frac{1kg}{1000g}=0.062kg

So compute the molality:

m=\frac{n_{solute}}{m_{solvent}}=\frac{0.39mol}{0.062kg}=6.2m

Regards.

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4 years ago
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