Answer:
have a nice day everyone :p
I've done many research projects on these types of topics. And with my given knowledge I am more than positive the answer should be C: ITS CHEAP AND EASY TO OBTAIN.
molarity = moles of solute/liters of solution
We know the moles of solute: 0.875 moles of glucose. We can easily determine the liters of solution by using the mass of water given (1.5 kg) and the density of water (approximately 1 kg/L): they're, for all intents and purposes, equal (the approximation isn't large enough to be appreciable here, nor would the volume of the solution appreciably change since the solute is a solid that will <em>dissolve into </em>the solvent). So, we have 1.5 L of solution.
Now, we plug in what we have:
molarity = 0.875 moles of glucose/1.5 L of solution = 0.58 M glucose
The answer is provided to two significant figures since we're given the mass of water to two significant figures.
Answer:
Explanation:
Hello,
In this case, 38 % is commonly a by mass concentration, meaning that we have 38 grams of solute (sulfuric acid) per 100 grams of solution (water+sulfuric acid):
Hence, we compute the moles of sulfuric acid in 38 grams by using its molar mass (98 g/mol):
Next, the volume of the solution in litres by using the density of the solution:
This is done since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in litres, thus we have:
On the other hand, the molality is defined as the ratio of the moles of the solute to the mass of the solvent in kilograms, thus, we compute the mass of water (solvent) as shown below:
So compute the molality:
Regards.
