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Katarina [22]
3 years ago
14

Consider a iron-silver voltaic cell that is constructed such that one half-cell consists of the iron, Fe, electrode immersed in

a Fe(NO3)3 solution, and the other half-cell consists of the silver, Ag, electrode immersed in a AgNO3 solution. The two electrodes are connected by a copper wire. The Fe electrode acts as the anode, and the Ag electrode acts as the cathode. To maintain electric neutrality, you add a KNO3 salt bridge separating the two half-cells. Use this information to solve Parts B, C, and D. Part B The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the iron-silver voltaic cell. Indicate the physical states of atoms and ions using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not include phases for electrons. Express your answer as a chemical equation.
Chemistry
1 answer:
MissTica3 years ago
6 0

Answer:

See explanation

Explanation:

In the voltaic cell, energy is produced by spontaneous chemical reaction. One half cell functions as the anode (in this case it is the Fe/Fe^2+ half cell) while the other half cell functions as the cathode (in this case it is the the Ag/Ag^+ half cell).

At the anode;

Fe(s) -----> Fe^2+(aq) + 2e

At the anode;

2Ag^+(aq) + 2e ------> 2 Ag(s)

Overall cell equation;

Fe(s) + 2Ag^+(aq)  ------> Fe^2+(aq) + 2 Ag(s)

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AlekseyPX

Answer:

the answer is convection

convection

6 0
3 years ago
The net ionic equation for formation of an aqueous solution of nii2 accompanied by evolution of co2 gas via mixing solid nico3 a
Tom [10]

Hey there!:

The balanced reaction is as follows

NiCO3(s) + 2HI(aq) ⇌ NiI2(aq) + CO2(g) + H2O(l)

The net ionic equation shows all the ions that react or change state. In this case, the only ion that does not change state is the I⁻ ion (in both reactant and product, it is aqueous).

Therefore the net ionic equation is:

NiCO3(s) + 2H⁺(aq) ⇌ Ni²⁺(aq) + CO2(g) + H2O(l)

Hope that helps!

8 0
3 years ago
Read 2 more answers
If the Ksp of NaCl is experimentally determined to be 43.9, then what is the concentration of Na (in M) when it begins to crysta
serg [7]

Answer:

6.63 M

Explanation:

NaCl(s) ---> Na^+(aq) + Cl^-(aq)

Given that [Na^+] = [Cl^-] = s

Where s= concentration of the both ions

Ksp = s^2

s= √Ksp

s= √43.9

s= 6.63 M

4 0
3 years ago
An atom has the following electron configuration.
avanturin [10]

Answer:

2

Explanation:

4s2 has 2 valence electrons

6 0
3 years ago
A new compound contains nitrogen, hydrogen, boron, and fluorine. The assay values are: nitrogen, 13.360%; hydrogen, 3.8455%; bor
AVprozaik [17]

The compound contains:

Nitrogen = 13.360%

Hydrogen = 3.8455%

Boron = 10.312%

This implies that for every 100 g of the substance:

Mass of nitrogen = 13.360 g

Mass of hydrogen = 3.8455 g

Mass of Boron = 10.312 g

Atomic mass of N = 14 g/mol

Atomic mass of H = 1 g/mol

Atomic mass of B = 11 g/mol

# moles of N = 13.360/14 = 0.9543

# moles of H = 3.8455/1 = 3.8455

# moles of B = 10.312/11 = 0.9375

Divide by the smallest # moles:

N = 0.9543/0.9375 = 1.02

H = 3.8455/0.9375 = 4.10

B = 0.9375/0.9375 = 1

Empirical formula = NH4B

4 0
3 years ago
Read 2 more answers
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