All categories

3 years ago

A reaction that has two compounds as reactants and two compounds as products is most likely a

Chemistry

1 answer:

ryzh [129]3 years ago

7 0

Answer:

synthesis reaction

Explanation:

A synthesis reaction occurs when two or more reactants combine to form a single product. In a decomposition reaction, one reactant breaks down into two or more products. This is the reverse of a synthesis reaction. Replacement reactions occur when elements switch places in compounds.

You might be interested in

Precambrian rocks were primarily which type of rocks?

nataly862011 [7]

B. sedimentary rocks

3 0

4 years ago

Predict the products of the electrolysis of molten nickel(II) iodide. Write an ionic half-equation for the formation of one of t

Daniel [21]

Answer:

See explanation

Explanation:

The electrolysis of nickel(II) iodide yields nickel solid and iodine gas.

In the oxidation half equation;

2I^-(aq)-------> I2(g) + 2e

In the reduction half equation;

Ni^2+(aq) + 2e -----> Ni(s)

These are the half equations of the process;

The overall equation is;

Ni^2+(aq) + 2I^-(aq)-------> NiI2

6 0

3 years ago

What functional group is found in an alcohol?

Contact [7]

Answer:

an alcohol is a Hydroxyl group due to the OH~ that is associated with it's molecules

5 0

3 years ago

Calculate ΔH and ΔStot when two copper blocks, each of mass 10.0 kg, one at 100°C and the other at 0°C, are placed in contact in

ira [324]

Explanation:

The given data is as follows.

m = 10.0 kg = 10,000 g (as 1 kg = 1000 g)

Initial temp. of block 1, $T_{1} = 100^{o}C$ = (100 + 273) K = 373 K

Initial temp. of block 2, $T_{2} = 0^{o}C$ = (0 + 273) K = 273 K

So, heat released by block 1 = heat gained by block 2

$mC \Delta T = mC \times \Delta T$

$10000 g \times 0.385 \times (T_{f} - 100)^{o}C = 10000 g \times 0.385 \times (0 - T_{f})^{o}C$

$T_{f} - 100^{o}C = 0^{o}C - T_{f}$

$2T_{f} = 100^{o}C$

$T_{f} = 50^{o}C$

Convert temperature into kelvin as (50 + 273) K = 323 K.

Also, we know that the relation between enthalpy and temperature change is as follows.

$\Delta H = mC \Delta T$

= $10000 g \times 0.385 J/K g \times 323 K$

= 1243550 J

or, = 1243.5 kJ

Now, calculate entropy change for block 1 as follows.

$\Delta S_{1} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{373}$

= $10000 g \times 0.385 J/K g \times -0.143$

= -554.12 J/K

Now, entropy change for block 2 is as follows.

$\Delta S_{2} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{273}$

= $10000 g \times 0.385 J/K g \times 0.168$

= 647.49 J/K

Hence, total entropy will be sum of entropy change of both the blocks.

$\Delta S_{total} = \Delta S_{1} + \Delta S_{2}$

= -554.12 J/K + 647.49 J/K

= 93.37 J/K

Thus, we can conclude that for the given reaction $\Delta H$ is 1243.5 kJ and $\Delta S_{total}$ is 93.37 J/K.

6 0

3 years ago

Equation below is used to determine the heat flux for convection

OLEGan [10]

Q=hc A (Ts-Ta)
q = heat transfered per unit time
A= heat transfer area of the surface
hc= convective heat transfer coefficient of the process
Ts= temperature of the surface
Ta= temperature of the air

7 0

4 years ago