Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
AD = AB
AD = 2r+8
AB = 5r-13
we need to find the value of r to find the total length
so 2r+8 = 5r-13
subtract 2r from each side:
8 = 3r -13
add 13 to each side:
21 = 3r
divide both sides by 3
r = 21 / 3 = 7
r=7
now we know r, so replace r with 7 in the equation for AD
AD = 2r+8 = 2(7) +8 = 14 +8 = 22
the answer is D. 22
Answer:
4/5 = 8/10
Step-by-step explanation:
x/5 = 8/10
x = 8/10 × 5
x = 4
The answer is D. Best of luck!
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