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3 years ago

13

Mario has 3 1/6 lbs of trail mix. He puts equal amounts of trail mix into 5 bags for his friends. If he uses all of the trail mi

x, how many lbs will be in each bag?
A) 19/30
B) 95/6
C) 15 1/6
D) 8 1/6

1 answer:

Angelina_Jolie [31]3 years ago

7 0

I think it’s C.

Hope this helps :)

Have a great day

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A freight elevator can hold a maximum weight of 3,500 pounds.

Brrunno [24]

Answer:

C

Step-by-step explanation:

$200 + 48c \leqslant 3500$

$48c \leqslant 3300$

$c \leqslant 68.75$

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2 years ago

At a fundraiser breakfast, the bill for three glasses of orange juice and five pancake specials is $7.60, whereas the bill for o

r-ruslan [8.4K]

A )
3 j + 5 p = 7.60
j + 2 p = 2.90
B )
j = 2.90 - 2 p
3 ( 2.90 - 2 p ) + 5 p = 7.60
8.70 - 6 p + 5 p = 7.60
p = $1.10
j = 2.90 - 2.20
j<span> = $0.70</span>
C )
The bill for 1 glass of orange juice and 1 pancake special would be:
0.70 + 1.10 = $1.80

3 0

3 years ago

I need help pleaseeeee this is due tomorrow

sveta [45]

Another way of finding Surface Area is

SA= 2LW+2LH+2HW

L= Length

W= Width

H= Height

the answer, and explained, would be this

2. SA= 2(12)(10)+2(12)(16)+2 (10)(16)

(<em>multiply</em>)

3. SA= 240 + 384 + 320

(<em>add</em>)

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em>.</em><em>.</em><em> </em>

<em><u>SA</u></em><em><u>=</u></em><em><u>944ft3</u></em><em><u> </u></em>

7 0

3 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

3 years ago

The temperature at noon was -17 degrees at 6 pm the temperature was -14 degrees. What was the change in temperature degrees?

irina [24]

Answer: the change in tempature was -3 degrees

Step-by-step explanation: hope this helps

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3 years ago