If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
Answer:
Step-by-step explanation:
D because it shows that 1x1/3 is shown on # D
Answer:
Step-by-step explanation:
Pemdas
so do parenthaseese first
work inside then out
(25 times 2)
(50)
now we have
96/42+(50)-15-3=?
start from the begining again of the equation (left) now we do division
96/42=16/7
now we have 16/7+(50)-15-3
start over and do addition
16/7+50=2 and 2/7+50=2+2/7+50=52 and 2/7
subtract
52 and 2/7-15=52+2/7-15=37 +2/7=37 and 2/7
then subtract 3
37 and 2/7-3=37+2/7-3=34+2/7=34 and 2/7
answer is 34 and 2/7
Since y + x = 3, then we could say one of them equals 2 while the other is 1. y - x = 1, then we can say 3 - 1 = 2, so y would be 2 and x would be 1
