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Zielflug [23.3K]
3 years ago
11

(1/7 + 7/11 + 2010/2011) + (6/7 + 4/11 - 2010/2011) = ?

Mathematics
2 answers:
Anni [7]3 years ago
6 0

Step-by-step explanation:

1/7 + 7/11 <em>+ 2010/2011</em> + 6/7 + 4/11 <em>- 2010/2011</em>

= 1/7 + 6/7 + 7/11 + 4/11

= 7/7 +11/11

= 1 + 1

= 2

Tresset [83]3 years ago
4 0

Step-by-step explanation:

2

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This morning Greg’s car had 25.25 of fuel now 1.4 gallons are left how much fuel did Greg use
tensa zangetsu [6.8K]

Answer:23.85

Step-by-step explanation:

8 0
3 years ago
Suppose that Clayton Kershaw of the Los Angeles Dodgers throws his fastball with a mean velocity of 94 miles per hour (mph) and
vekshin1

Answer:

Step-by-step explanation:

ah,  probability,  so the std. deviation is 2 MPH,  so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations  or  6 MPH to hit 100

99.7%  of throws fall into that area of with in 3 std. deviations so that means

0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast

so

0.15%  will be 100 or faster.... not many

8 0
2 years ago
I need help with these two equations
Ivan

for these you need to rearrange the equations and do substitutions.

 #3 = if x+y=5 then you know x = 5-y

 now substitute that equation for x in the 2nd one so x + 2y = 8 becomes

5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3

now replace y with 3 in the first equation x = 5-3 so x = 2 

 so (2,3) is the answer


 same type of work for #4

2x-y=6 ,S0 y = 2X+6

 so now you have 4x+2(2x+6)=-4

that becomes 4x +4x+12 = -4

8x+8 = 1, x =1

y = 2(1)-6 = -4

 so answer is (1,-4)

7 0
3 years ago
What is 30/45 simplest form
Marysya12 [62]
\dfrac{30}{45}=\dfrac{30:15}{45:15}=\dfrac{2}{3}
5 0
3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?
olga2289 [7]

Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

<u>Find the equation of the line with mCD and the point (3,0)</u>

we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

4 0
2 years ago
Read 2 more answers
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