A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say
x.
The lateral faces are equilateral triangles of side length
x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find
x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:

thus,

thus:

(cm^2)
but

is exactly the base area, since the base is a square of sidelength =
x cm.
So, the total surface area = base area + lateral area =

cm^2
Answer:

cm^2
Answer:
the 2nd is the answer
Step-by-step explanation:
The last side would be 10
Answer:
the answers are B,C,D
Step-by-step explanation:
Answer: Slope = 3/4 | down 3 over 4
Step-by-step explanation: First I went into desmos graphing calc and then marked the two points (-20,-4) and on a seprete line marked (-12,-10) and then i took a ruler and put up to my screen to see if there was a simplified answer (ex: 2/4 = 1/2) there was not so I just went down to the y line of the 2nd dot which turned out to be 3 and then just counted over to the dot which was 4 units.