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frozen [14]
2 years ago
11

Evaluate y = -4(5)* for x = 2

Mathematics
1 answer:
lakkis [162]2 years ago
4 0

Answer: Y= -10

Step-by-step explanation:

You might be interested in
A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

3 0
2 years ago
5(8n+ 7) < 5-5(n+3)
svet-max [94.6K]

Answer:

n<-1

Step-by-step explanation:

Distribute 5 and -5 into each parenthesis respectively: 40n+35<5-5n-15

Combine like terms: 40n+35<-5n-10

Add 5n to both sides: 45n+35<-10

Subtract 35 from both sides: 45n<-45

Divide both sides by 45: n<-1

3 0
2 years ago
Suppose 8x + 16 ice cream cones
kvv77 [185]

Answer:

B. 152 + 7

Step-by-step explanation:

(8x + 16) + (7x - 9)

8x + 16 + 7x - 9

15x + 16 - 9

15x + 7

None of these options have this answer, so we see A and B:

A. x + 7

B. 152 + 7

It can't be A because we have 15x and A is x + 7

By process of elimination we have B. 152 + 7

x = 10 and 2/15

8 0
2 years ago
What's the answer to this math picture please?
professor190 [17]

Answer:

m<BGC = 145°

Step-by-step explanation:

<AGC and <DGB are vertical angles. Vertical angles are congruent. Therefore:

m<AGC = m<DGB

3x + 20 = 8x - 5 (substitution)

Collect like terms

3x - 8x = -20 - 5

-5x = -25

Divide both sides by -5

x = 5

m<BGC = 180 - (m<AGC) (linear pair)

m<BGC = 180 - (3x + 20)

Plug in the value of x

m<BGC = 180 - (3(5) + 20) = 180 - 35

m<BGC = 145°

3 0
3 years ago
I am a odd number less than 100 and a multiple of 15.The sum of my digits is 12.What number am I.
lutik1710 [3]
The number is 75
15*3=75
75<100
7+5=12
75 is odd
6 0
3 years ago
Read 2 more answers
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