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Sedbober [7]
3 years ago
5

In the polynomial function F(x)=1/2x^2+8-5x^3-19x what is the leading the coefficient

Mathematics
2 answers:
Dima020 [189]3 years ago
8 0
The leading coefficient  is in the term with the highest degree.
So its -5.
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

-5

Step-by-step explanation:

The leading term in a polynomial consist on the highest degree term.  To get the highest degree term, we need to reorder the polynomial from left to right, starting with the highest degree term.

In this case:

f(x)=\frac{1}{2} x^{2} +8-5x^{3} -19x

reordering

f(x)=-5x^{3} +\frac{1}{2}x^{2}  -19x+8

So, the leading coefficient is the one with the leading term:

-5x^{3}

So, it is <em>-5</em>

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When Jared found 1/5 +2/5,he wrote the sum 3/10 is Jared correct
damaskus [11]

Answer:

Step-by-step explanation:

no, he is not. He literally added the numerators and the denominators. When ur adding fractions with the same denominator, u just add the numerators and keep the same denominator.

1/5 + 2/5 = 3/5

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How you do multiply complex numbers ? Example : (9 - 4i) (8 + 6i)
Andrew [12]

You multiply them just as you would multiply any normal polynomials, except there is a special rule. Since we know that i = √-1, the rule is that i² = -1. So, let's multiply:

(9-4i)(8+6i) = 72+54i-32i-24i^2

Let's simplify this:

72+22i+(-24*-1)

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Which of the following logarithms do not exist?
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B. logarithms of negative number don't exist

5 0
3 years ago
Maitri and Aabhas do a work in 12 hours.
tamaranim1 [39]

Answer:

See below ~

Step-by-step explanation:

<u>Given</u>

  • Maitri and Aabhas do a work in 12 hours
  • Aabhas and Kavya do the work in 15 hours
  • Kavya and Maitri do the work in 20 hours

<u>Solving</u>

  • Take Maitri, Aabhas, and Kavya to be x, y, z respectively
  • <u>x + y = 12</u> (1)
  • <u>y + z = 15</u> (2)
  • <u>x + z = 20</u> (3)

<u>Take Equation 1 and rewrite it so that it is equal to x.</u>

  • x = 12 - y

<u>Take Equation 2 and rewrite it so that it is equal to z.</u>

  • z = 15 - y

<u>Now, substitute these values in Equation 3.</u>

  • x + z = 20
  • 12 - y + 15 - y = 20
  • -2y + 27 = 20
  • 2y = 7
  • y = 7/2 = <u>3.5 hours [Aabhas]</u>

<u></u>

<u>Substitute the value of y in Equation 1.</u>

  • x + 3.5 = 12
  • x = <u>8.5 hours [Maitri]</u>

<u>Substitute the value of y in Equation 2.</u>

  • 3.5 + z = 15
  • z = <u>11.5 hours [Kavya]</u>

<u></u>

<u>Add the values of x, y, and z together.</u>

  • x + y + z
  • 8.5 + 3.5 + 11.5
  • 12 + 11.5
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