
This is the solution of the equation, where a=1, b=-5, c=7
So the discriminant is :
b^2-4ac=25-4*7= -3
The square root of -3 is non-real, this both solutions are non-real.
Answer:

and t ∈ [0,2π]
Step-by-step explanation:
The standard equation for circle is:

Comparing our equation with standard

h= 0,
k= 3
r= 4 (as in standard r², so r =√ r²)
Required:
Parametric equations of the circle
Formula:

Putting values of r and h and k we get

As we need to start the object at (4,3)
x(0) = 4 and y(0) = 3
and the period is 2π
As the rotation is starting clock wise we will invert the value of t i.e -t

and t ∈ [0,2π]
Answer:
Step-by-step explanation:
∠CFE is made up of ∠3 + ∠4; therefore,
∠3 + ∠4 = 74
∠BFD is made up of ∠2 + ∠3; therefore,
∠2 + ∠3 = 103
∠BFE is made up of ∠2 + ∠3 + ∠4; therefore,
∠2 + ∠3 + ∠4 = 136
and we are looking for the measure of ∠CFD which is ∠3.
Begin by using the fact that ∠3 + ∠4 = 74 and sub that into ∠BFE:
∠BFE = 136 and
∠2 + (∠3 + ∠4) = 136 and
∠2 + 74 = 136 so
∠2 = 62
Now use that in ∠BFD since
∠BFD = 103 and
∠2 + ∠3 = 103 and
62 + ∠3 = 103 so
∠3 = 41
It would be

indicating we start at 5 but do NOT include 5, and we keep going onward to positive infinity.
The curved parenthesis tells us not to include the endpoint.