Answer: From highest to lowest, we have Iron> water> hydrogen
Explanation: Condensation temperature is temperature at which materials transit from being a vapor to being a solid.The early solar nebula consisted of water, iron and hydrogen, and the temperature in the nebula is said to decrease with distance away from the proto-sun, with heavy elements such as iron whose distance is nearer to the protosun, will have a higher condensation temperature as compared to light elements, such as hydrogen which have lower temperature since gases are further from the sun. water vapour is heavier than hydrogen and therefore will have a higher condensation temperature than hydrogen.
The volume of Hydrogen gas : 24 L
<h3>Further explanation</h3>
Given
16 L Ammonia(NH₃)
Required
The volume of Hydrogen gas
Solution
Reaction
N₂ + 3H₂ ⇒ 2NH₃
Avogadro's hypothesis:
In the same T,P and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so volume of H₂ :
= 3/2 x volume of NH₃
= 3/2 x 16 L
= 24 L
Answer:
- The answer is the concentration of an NaOH = 1.6 M
Explanation:
The most common way to solve this kind of problem is to use the formula
In your problem,
For NaOH
C₁ =?? v₁= 78.0 mL = 0.078 L
For H₂SO₄
C₁ =1.25 M v₁= 50.0 mL = 0.05 L
but you must note that for the reaction of NaOH with H₂SO₄
2 mol of NaOH raect with 1 mol H₂SO₄
So, by applying in above formula
- (C₁ * 0.078 L) = (2* 1.25 M * 0.05 L)
- C₁ = (2* 1.25 M * 0.05 L) / (0.078 L) = 1.6 M
<u>So, the answer is the concentration of an NaOH = 1.6 M</u>
Answer:
14 J of heat
Explanation:
Recall that the enthalpy of reaction is defined as the enthalpy change that occurs in a system when matter is transformed by a given chemical reaction, if all reactants and products are in their standard states. Here we have the heat of formation of six moles of the substance and we are expected to use it to obtain the the heat of formation of one mole of the compound and we can do that by simple proportion as shown below;
If 6 moles of the compound produces 84J of heat
1 mole of the substance will produce 1×84/6 = 14 J of heat
