Answer:
The answer to your question is 3 ml
Explanation:
Data
Dosage = 9.0 mg/ kg
Child's weight = 42.9 pounds
Suspension = 60 mg/ml
milliliters = ?
Process
1.- Convert the weight to kg
1 pound ------------------- 0.453 kg
42.9 pounds --------------- x
x = (42.9 x 0.453) / 1
x = 19.43 kg
2.- Calculate the milligrams the child needs
1 kg of weight ------------ 9 mg
19.43 kg ---------------------- x
x = (19.43 x 9) / 1
x = 174.87 mg of oxcarbazepine
3.- Calculate the milliliters needed
60 mg of suspension ------------- 1 milliliters
174.87 mg -------------- x
x = (174.87 x 1) / 60
x = 2.9 ml ≈ 3 ml
The balanced chemical reaction would be:
FeS(s)+2HCl(aq)→FeCl2(s)+H2S(g)
We are given the amount of the reactants to be used for the reaction. We use these amounts. First, we determine the limiting reactant of the reaction. From the data, we can say that FeS is the limiting ad HCl is the excess reactant. We calculate as follows:
Amount of HCl used: 0.240 mol FeS x 2 mol HCl / 1 mol FeS = 0.48 mol HCl
0.646 - 0.48 = 0.166 mol HCl left
Answer:
option a and c both are correct
Explanation:
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Answer is: 0,0095 mol of hydrogen gas will be produced in reaction.
Chemical reaction: Ca + 2HCl → CaCl₂ + H₂.
m(Ca) = 0,38 g.
n(H₂) = ?
n(Ca) = m(Ca) ÷ M(Ca).
n(Ca) = 0,38 g ÷ 40 g/mol
n(Ca) = 0,0095 mol.
from reaction: n(Ca) : n(H₂) = 1 : 1.
n(H₂) = n(Ca) = 0,0095 mol.
n - amount of substance.
Answer:
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