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erik [133]
3 years ago
12

What is the difference between asexual and sexual

Chemistry
2 answers:
nevsk [136]3 years ago
5 0
Asexual reproduction only requires one parent organism. The daughter cells are copies of the original cell that divided to create the daughter cells. Sexual reproduction requires two parent organisms. The two parent cells combine to form a new unique daughter cell.
Alex_Xolod [135]3 years ago
3 0

Answer:

a

Explanation:

The difference between asexual and sexual is one letter "a". this is becuase if you subtract the first letter a off of asexual then you get sexual.

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Percent occurrence and isotope masses for oxygen: 99.759 % at 15.99491 amu, 0.037% at 16.99913 amu and 0.204% is at what amu val
Masja [62]

Answer:

15.99937 is the value of this question answer

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What mass of calcium hydroxide is formed when 10.0g of calcium oxide reacts with 10.0g of water?
nexus9112 [7]

The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with  10.0 g of water is 13.024 grams


calculation

from the equation

CaO + H2O → Ca(OH)2,

 1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2

find the moles of each reactant

moles=mass/molar mass

moles of CaO= 10 g/56 g/mol=0.179 moles

moles of H2O = 10 g/18 g/mol 0.556  moles

CaO is the limiting reagent  therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles

mass= moles x molar mass

= 0.176 moles x  74 g/mol = 13.024  grams

7 0
4 years ago
Which scientist developed the 1st model of the atom that showed the structure of the inside of an atom?
frez [133]
C. Rutherford (1911)
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Why do atoms always have an overall neutral charge?
PSYCHO15rus [73]
This means the nucleus of an atom is always positively charged
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Read 2 more answers
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the
emmasim [6.3K]

Answer:

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

Explanation:

From the given information:

The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.

In this  same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;

Rate factor in the absence of catalyst:

k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}

Rate factor in the presence of catalyst:

k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}

Assuming the catalyzed reaction and the uncatalyzed reaction are  taking place at the same temperature :

Then;

the ratio of the rate factors can be expressed as:

\dfrac{k_2}{k_1}={  \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}

\dfrac{k_2}{k_1}={  \dfrac {e^{[  Ea_1 - Ea_2 ] }}{RT} }}

Thus;

Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}

Let say the assumed temperature = 25° C

= (25+ 273)K

= 298 K

Then ;

Ea_1-Ea_2 = 8.314 \  J/mol/K * 298 \ K *  In (10^6)

Ea_1-Ea_2 = 34228.92 \ J/mol

\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

8 0
3 years ago
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