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2 years ago

Approximate the number to the nearest (a) integer and (b) tenth. Please help

Mathematics

1 answer:

lakkis [162]2 years ago

6 0

Answer:

a. 3

b. 2.9

Step-by-step explanation:

$\sqrt[3]{25} ≈2.92$

a. An integer is a whole number. the nearest whole number to 2.92 is 3.

b. 2.92 rounds down to 2.9 when rounding the the tenths' place.

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Solve the system by elimination 3x-2y=3 15x-4y=-3

stiv31 [10]

Answer:

x=-1

y=-3

Step-by-step explanation:

3x-2y=3(1)

5.(1) <=> 15x-10y=15 (2)

15x-4y=-3 (3)

(2)-(3) <=> -6y=18

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2 years ago

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Answer: 132 degrees

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2 years ago

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Only do question 17 50 points Topic: Percentage

ZanzabumX [31]

Answer:

see below

Step-by-step explanation:

Cedarville

Year 1

1200 * 8% = 96 people

At the end the population is 1296

Year 2

1296 * 7% =90.72

1296+90.72 =1386.72 people

Pinedale

1200*15%=180

1200+180 = 1380

Cedarville has more people at the end of 2 years by 6.72 people

3 0

2 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is 1.5IQR above the 75th percentile, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

A similar problem is given at brainly.com/question/15683591

3 0

2 years ago

5. A gardening club has 21 members, of which 13 are males and the rest are

Misha Larkins [42]

If you know that there are 21 members and 13 are females, if you subtract 13 from 21, you will get 8. There are 8 females in the gardening club.

Now you have to figure out the ratio to females to all club members. You already know that there are 8 females and 21 club members. The ratio would be 8:21.

I hope you found this helpful :)

3 0

3 years ago

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