2(3x + 5) = 9x + 9 - 3x + 1

1 answer:

3 0

2(3x+5)=9x+9-3x+1
(2)(3x)+(2)(5)=9x+9-3x+1
6x+10=9x+9-3x+1
6x+10=(9x-3x)+(9+1)
6x+10=6x+10
6x-6x+10=6x-6x+10
10=10
10-10=10-10
0=0
All real numbers are solutions.

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2(3x + 5) = 9x + 9 - 3x + 1​

2(3x + 5) = 9x + 9 - 3x + 1