Answer:
The length of rectangle is 16 meters and the width of rectangle is 7 meters
Step-by-step explanation:
Let
L -----> the length of the rectangle
W ---> the width of the rectangle
we know that
The perimeter of rectangle is equal to
----> the perimeter of a rectangle is twice the sum of its length and its width
we have
so
simplify
-----> equation A
----> equation B
substitute equation B in equation A and solve for W
Find the value of L
therefore
The length of rectangle is 16 meters and the width of rectangle is 7 meters
62 because 90 minus 15, minus 13, is equal to 62
Answer: (3.5,-2)
Step-by-step explanation:
To solve this problem, all we have to do is plug in y=-2 into either equations from step one to find the coordinate. To make sure we have the right x-coordinate, let's plug in y for both equations.
4x-7y=28 [plug in y=-2]
4x-7(-2)=28 [multiply]
4x+14=28 [subtract both sides by 14]
4x=14 [divide both sides by 4]
x=3.5
------------------------------------------------------------------------------------------------------------
6x-5y=31 [plug in y=-2]
6x-5(-2)=31 [multiply]
6x+10=31 [subtract both sides by 10]
6x=21 [divide both sides by 6]
x=3.5
Now, we know the solution to the system is (3.5,-2).
Answer:
92 sq. inches
Step-by-step explanation:
Total paper required = total surface area
Surface area of a cuboid = 2[(l×b) + (l×h) + (b×h)],
Where 'l' is the length, 'b' is the breadth and 'h' is the height
For the box, total surface area = 2[(8×3) + (3×2) + (8×2)]
=2[24 + 6 + 16]
=2[46]
= 92 sq. inches