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Alekssandra [29.7K]

3 years ago

15

Ruben put an empty cup underneath a leaking faucet. After 1-1/2 hours, Ruben had collected 1/4 cup. What is the rate, in cups pe

r hour, at which the water is leaking from the faucet?

1 answer:

vovikov84 [41]3 years ago

8 0

0.1666666667 cups of water
90 mins = 0.25
60 min = 0.1666666667

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3 years ago

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3 years ago

A city is holding a referendum on increasing property taxes to pay for a new high school. In a survey of 458 likely voters, 254

Phantasy [73]

Answer:

$\hat p \pm Z*\sqrt{\frac{\hat p\times(1-\hat p)}{n} }$

$=0.5546\pm1.96*\sqrt{\frac{0.5546\times(1-0.5546)}{458} }$

$=0.5546\pm1.96*\sqrt{\frac{0.5546\times(0.4454)}{458} }$

$=0.5546\pm1.96*\sqrt{\frac{0.2470}{458} }$

$=0.5546\pm1.96*\sqrt{0.00053934}$

$=(0.5091,0.6001)$

Lower limit for confidence interval=0.5091

Upper limit for confidence interval=0.6001

Step-by-step explanation:

We have given,

x=254

n=458

Estimate for sample proportion= $\bar p = 0.5546$

Level of significance is =1-0.95=0.05

Z critical value(using Z table)=1.96

Confidence interval formula is

$\hat p \pm Z*\sqrt{\frac{\hat p\times(1-\hat p)}{n} }$

$=0.5546\pm1.96*\sqrt{\frac{0.5546\times(1-0.5546)}{458} }$

$=0.5546\pm1.96*\sqrt{\frac{0.5546\times(0.4454)}{458} }$

$=0.5546\pm1.96*\sqrt{\frac{0.2470}{458} }$

$=0.5546\pm1.96*\sqrt{0.00053934}$

$=(0.5091,0.6001)$

Lower limit for confidence interval=0.5091

Upper limit for confidence interval=0.6001

8 0

3 years ago

Find the complement of 63°

Alika [10]

Answer:

63=90-63= 27

Bye

3 0

3 years ago