Log 3(x²+6x)=log(2x+12). I assume that 3 is a factor of a log with base 10:
if so, then:
log(3x²+18x)=log(2x+12)
==> 3x²+18x=2x+12==> 3x²+16x-12 = 0
solve this quadratic equation & you will find: x'=2/3 & x"=-6
Hey there!
The possible ratios for this math problem other than 2:5 would probably be:
4:10, 8:20, 16:40 and so on.
Hope this helps!
Have a great day!
Answer:
(-1.85, -0.15)
Step-by-step explanation:
Here,
x1 = -5.1
x2 = 1.4
y1 = -2
y2 = 1.7
Now substituting the values we have in the equation, we get:-
The coordinates of the midpoint would be = (-1.85, -0.15)
Answer:
the correct answer is 2,432
In order to identify the mean distance jogged by Jim for 6 days, we add up all of the distances and divide the sum by 6. That is,
sum = 6.5 + 5 + 3 + 2 + 3.5 + 4 miles
sum = 24 miles
Dividing the sum by 6 will give us an answer of 4 miles. Thus, Jim jogged an average of 4 miles for 6 days.
