Let x represent the number of A printers
<span>Let y represent the number of B printers </span>
<span>Minimize cost = 86x + 130y </span>
<span>subject to </span>
<span>Total printers equn: x + y ≥ 100 </span>
<span>Total profit equn: 45x + 35y ≥ 3850 </span>
<span>x ≥ 0, y ≥ 0 </span>
<span>x and y must be whole numbers. </span>
<span>The vertices of the feasible region are: (0, 100), (100, 0) and (35, 65) </span>
<span>If x = 35 and y = 65 the cost is 11460 and profit is 3850 </span>
<span>if x = 100 and y = 0 the cost is 8600 and profit is 4500 </span>
<span>If x = 0 and y = 100 the cost is 13000 and profit is 3500 </span>
<span>The best result is x = 100 and y = 0</span>
Answer:
6^27
Step-by-step explanation:
To answer this, we are going to use one of the laws of indices
We have this as;
(a^b)^c = a^(b * c) = a^bc
we are going to apply same here
(6^-3)^-9 = 6^(-3 * -9) = 6^27
Answer:
51, 52, 53
Step-by-step explanation:
51, 52, and 53 are all greater than 50, but less than 54
(3.5x1016) = 3556
and
(2.2x1010) = 2222
As per question;
(3556)x(2222) = 10 a*b
By dividing both sides by "10"
we get
(3556)x(222.2) = a*b
or
(355.6)x(2222) = a*b
by comparing both sides of the equation,
we get that a = 3556 and b = 222.2
or
a = 355.6 and b = 2222
