Their average velocity is 0.98 m/s east.
Explanation:
The average velocity of an object is defined as the ratio between the displacement and the time taken:
![v=\frac{displacement}{time}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bdisplacement%7D%7Btime%7D)
The displacement is a vector connecting the initial point to the final point of motion: so, being displacement a vector, velocity is a vector as well, having the same direction of displacement.
Here, Heather and Matt walk 2.0 km eastward, so their displacement is
d = 2.0 km = 2000 m (east)
While the time they took is
![t=34 min \cdot 60 = 2040 s](https://tex.z-dn.net/?f=t%3D34%20min%20%5Ccdot%2060%20%3D%202040%20s)
Therefore, their average velocity is
![v=\frac{2000}{2040}=0.98 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2000%7D%7B2040%7D%3D0.98%20m%2Fs)
And the direction is the same as the displacement (east).
Learn more about average velocity:
brainly.com/question/5248528
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Explanation:
<em>For</em><em>ce</em><em> </em><em>per</em><em> </em><em>uni</em><em>t</em><em> </em><em>area</em><em> </em><em>is</em><em> </em><em>call</em><em>ed</em><em> </em><em>Pres</em><em>sure</em><em>.</em>
Answer:
Option B. 2.8 s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 27 m/s
Angle of projection (θ) = 30
Acceleration due to gravity (g) = 9.8 m/s²
Time of flight (T) =?
The time of flight of the ball can be obtained as follow:
T = 2uSineθ / g
T = 2 × 27 × Sine 30 / 9.8
T = 2 × 27 × 0.5 / 9.8
T = 27 / 9.8
T = 2.8 s
Therefore, time of flight of the ball is 2.8 s
Answer:
The centre of the earth is harder to study than the centre of the sun." Temperatures in the lower mantle the reach around 3,000-3,500 degrees Celsius and the barometer reads about 125 gigapascals, about one and a quarter million times atmospheric pressure.
Explanation:
Answer:
3.6 x 10⁶ Pa
Explanation:
A = Area of the heel = 1.50 cm² = 1.50 x 10⁻⁴ m²
m = mass of the woman = 55.0 kg
g = acceleration due to gravity = 9.8 m/s²
Force of gravity on the heel is given as
F = mg
Inserting the values
F = (55) (9.8)
F = 539 N
Pressure exerted on the floor is given as
![P = \frac{F}{A}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BF%7D%7BA%7D)
![P = \frac{539}{1.5\times 10^{-4}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B539%7D%7B1.5%5Ctimes%2010%5E%7B-4%7D%7D)
P = 3.6 x 10⁶ Pa