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He had their masses and reactivity. I hope this helps.
Answer:
because the strength of Earth's gravitational field is not uniform everywhere, a given pendulum swings faster, and thus has a shorter period, at low altitudes and at Earth's poles than it does at high altitudes and at the Equator.
According to Boyle-Mariotte:
p₁V₁=p₂V₂=>V₂=p₁V₁/p₂= 0.0024*101.70/ 84.16=0.0028 m³
Answer:
a) w = 9.599 10⁴ rad / s
, b) v = 3.35 10¹⁶ m / s
, c) a = 3.22 10²¹ m / s²
Explanation:
For this exercise we must use the relation of angular kinematics
a) angular velocity, the distance remembered in orbit between time (period)
w = 2π r / T
w = 2 π 3.59 10¹¹ / 2.35 10⁷
w = 9.599 10⁴ rad / s
b) linear and angular velocity are related by the equation
v = w r
v = 9,599 10⁴ 3.49 10¹¹
v = 3.35 10¹⁶ m / s
c) the centripetal acceleration is
a = v² / r = w² r
a = (9,599 10⁴)² 3.49 10¹¹
a = 3.22 10²¹ m / s²