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jenyasd209 [6]
2 years ago
12

What causes heat flow

Physics
1 answer:
Alex787 [66]2 years ago
4 0

Answer:

Heat flow is the movement of heat.

Explanation:

Heat flows in solids by conduction, which occurs when two objects in contact with each other transfer heat between them. That happens because the molecules hit each other, and the faster moving molecules in the hot object spread that energy into the cooler object

Credit to, https://study.com/academy/lesson/heat-flow-in-solids-fluids.html

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Which layer(s) of Earth participate(s) in plate tectonics? Select all that apply.
mafiozo [28]
I am pretty sure it is A and D
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3 years ago
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**HELP ASAP**
Tcecarenko [31]
The answer of this question is B.
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3 years ago
A spherical conductor is inside a uniform electric field with a magnitude of 1000 N/C to the right. What is the magnitude and di
Lyrx [107]

Answer:

1.-E=1000N/C to the LEFT

2.-The electric field inside a conductor in electrostatic state is always zero (conductor proprieties).

3.-The voltmeter read 0V as differential voltage between two points from the conductor

Explanation:

1.The electric field inside the conductor must be zero (conductor proprieties). Then the charges create a electric field equal an opposite to the external electric field. In other words E=1000N/C to the LEFT

2. The electric field inside a conductor in electrostatic state is always zero. As shown in the figure the electric field induced by the charges in the sphere surface cancelled the EXTERN electric field.

3.If the Electric field inside the conductor is zero, that means that the Voltage in the hole conductor is constant (conductor proprieties). In other words the the voltmeter read 0v as differential voltage between two points from the conductor.

3 0
3 years ago
You have 2 minutes to get to PE from science class before you get a tardy. If PE is 100m away and you walk at a speed of 1.1m/s
mart [117]

Answer:

D

Explanation:

4 0
3 years ago
Read 2 more answers
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
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