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2 years ago

The front end of the car is crushing and absorbing ___ which slows down the rest of the car

Physics

1 answer:

Luda [366]2 years ago

8 0

The answer is energy

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Give an equation for kinetic energy<br>(supplement)

Leya [2.2K]

Answer:

The equatiom of kinetic energy is 1/2×m×v² where m represents mass and v is velocity :

$k.e = \frac{1}{2}m {v}^{2}$

The unit for kinetic energy is measured in Joules (J).

6 0

2 years ago

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma

Oksanka [162]

Answer:

Explanation:

The momentum of the first piece = m v =- m x 31 i kg m/s in - x direction direction

The momentum of the second piece = -m x 31 j kg m /s in Y - direction

Total momentum = - 31 m( i + j )

To conserve momentum , the third piece must have momentum equal to this

and opposite to it

So momentum of the third piece = 3m x V = 31 m ( i +j )

V = 31/3 ( i + j ) =

Magnitude of velocity V = √2 x 31/ 3 = 14.6 m / s

Its direction will be towards the vector i + j ie 45° from x - axis in positive direction

4 0

3 years ago

Will mark as BRAINLIEST.......

irinina [24]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

$x=4t^3+3t^2-5t+2$

Where,

x is in meters and t is in sec

We know that,

Velocity,

$v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5$

(a) i. t = 2 s

$v=12(2)^2+6(2)-5=55\ m/s$

At t = 4 s

$v=12(4)^2+6(4)-5=211\ m/s$

(b) Acceleration,

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6$

Pu t = 3 s in above equation

So,

$a=24(3)+6\\\\a=78\ m/s^2$

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²

6 0

3 years ago

Scientific notation 325

Anni [7]

3.25 x 10^2 (ten to the second power)

7 0

2 years ago

a races car travels on a circular track at an average rate of 125mi/h the radius of fhe track is 0.320 miles what is that centri

Sholpan [36]

390.625
I hope this helps

6 0

2 years ago