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siniylev [52]
3 years ago
9

What distance does a police car travel if it is going 3.0 m/s for 20 seconds

Physics
1 answer:
Vladimir79 [104]3 years ago
6 0

Answer:

60 meters

Explanation:

If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply

3meters/second*20seconds

cross out the seconds and you have

3 meters*20

60 meters

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What effect does the Boat Velocity have on the waves seen by the observer?
photoshop1234 [79]

sbjananaan swhhwvwwhehs

5 0
3 years ago
Work done= ________ transferred
mamaluj [8]

Answer:

Work done= Energy transferred

Explanation:

Work is the transfer of energy. In physics we say that work is done on an object when you transfer energy to that object. If you put energy into an object, then you do work on that object (mass).

4 0
3 years ago
A transformer has a primary coil with 375 turns of wire and a secondary coil with 1,875 turns. An AC voltage source connected ac
Sonbull [250]

Answer:

The rms voltage (in V) measured across the secondary coil is 459.62 V

Explanation:

Given;

number of turns in the primary coil, Np = 375 turns

number of turns in the secondary coil, Ns = 1875 turns

peak voltage across the primary coil, Ep = 130 V

peak voltage across the secondary coil, Es = ?

\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V

The rms voltage (in V) measured across the secondary coil is calculated as;

V_{rms} = \frac{V_0}{\sqrt{2} } = \frac{E_s}{\sqrt{2} } \\\\V_{rms} = \frac{650}{\sqrt{2} } = 459.62 \ V

Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V

7 0
3 years ago
A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk
malfutka [58]

Answer:

The mass of the cargo is M  =  188.43 \ kg

Explanation:

From the question we are told that

    The radius of the spherical balloon is  r =  7.40 \ m

     The mass of the balloon is  m = 990\ kg  

The volume of the spherical balloon is mathematically represented as

     V  =  \frac{4}{3} * \pi r^3

substituting values

      V  =  \frac{4}{3} * 3.142 *(7.40)^3

      V  =  1697.6 \ m^3

The total mass  the balloon can lift is mathematically represented as

     m =  V (\rho_h - \rho_a)

where \rho_h is the density of helium with a  value of

       \rho_h  =  0.179 \ kg /m^3

and  \rho_a is the density of air with a value of

        \rho_ a  = 1.29 \ kg / m^3

substituting values

          m =  1697.6 ( 1.29  - 0.179)

         m =  1886.0  \ kg

Now the mass of the cargo is mathematically evaluated as

        M  =  1886.0 - 1697.6

        M  =  188.43 \ kg

       

5 0
3 years ago
a stone is thrown by a person from the top of the building, which is 200m tall. at the same time, another stone is thrown with v
solniwko [45]

Answer:

The time after which the two stones meet is tₓ = 4 s

Explanation:

Given data,

The height of the building, h = 200 m

The velocity of the stone thrown from foot of the building, U = 50 m/s

Using the II equation of motion

                             S = ut + ½ gt²

Let tₓ be the time where the two stones  meet and x be the distance covered from the top of the building

The equation for the stone dropped from top of the building becomes

                            x = 0 + ½ gtₓ²

The equation for the stone thrown from the base becomes

                S - x = U tₓ - ½ gtₓ²  (∵ the motion of the stone is in opposite direction)

Adding these two equations,

                      x + (S - x) = U tₓ

                               S = U tₓ

                               200 = 50 tₓ

∴                                  tₓ = 4 s

Hence, the time after which the two stones meet is tₓ = 4 s   

6 0
3 years ago
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