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S_A_V [24]
3 years ago
8

Show that x + y : x - y= 3 : 2

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

x + y : x - y = (5/2+1/2) : (5/2-1/2)

x + y : x - y = 3 : 2

Therefore,  x + y : x - y= 3 : 2 is proved.

Step-by-step explanation:

Given

x + y : x - y = 3 : 2

As

x + y = 3

x - y = 2

Solving to find x and y

\begin{bmatrix}x+y=3\\ x-y=2\end{bmatrix}

x-y=2

-

\underline{x+y=3}

-2y=-1

\begin{bmatrix}x+y=3\\ -2y=-1\end{bmatrix}

solve for y

-2y=-1

Divide both sides by 2

\frac{-2y}{-2}=\frac{-1}{-2}

y=\frac{1}{2}

\mathrm{For\:}x+y=3\mathrm{\:plug\:in\:}y=\frac{1}{2}

x+\frac{1}{2}=3

x+\frac{1}{2}-\frac{1}{2}=3-\frac{1}{2}

x=\frac{5}{2}

so

x=\frac{5}{2},\:y=\frac{1}{2}

Thus,

x + y : x - y = (5/2+1/2) : (5/2-1/2)

x + y : x - y = 3 : 2

Therefore,  x + y : x - y= 3 : 2 is proved.

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Estimate the sum of 23 and 71
Natali [406]
Estimation:

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8 0
3 years ago
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Which of the following is a solution to the following system of inequalities?
iren2701 [21]

Option D: (0,3) is the solution to the inequalities.

Explanation:

From the given graph, we can see that the equation of the inequalities are

$y>-x+1$ and $y\leq 2 x+3$

To determine the coordinate that satisfies the inequality, let us substitute the coordinates in both of the inequalities $y>-x+1$ and $y

Thus, we have,

Option A: (1,-1)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies-1>0 is not true.

$y\leq 2 x+3 \implies -1\leq 5 is true.

Since, only one equation satisfies the condition, the coordinate (1,-1) is not a solution.

Hence, Option A is not the correct answer.

Option B: (-4,0)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies0>5 is not true.

$y\leq 2 x+3 \implies 0\leq -5 is not true.

Since, both the equations does not satisfy the condition, the coordinate (-4,0) is not a solution.

Hence, Option B is not the correct answer.

Option C: (3,-2)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies-2>-2 is not true.

$y\leq 2 x+3 \implies -2\leq 9 is true.

Since, only one equation satisfies the condition, the coordinate (3,-2) is not a solution.

Hence, Option C is not the correct answer.

Option D: (0,3)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies3>1 is true.

$y\leq 2 x+3 \implies 3\leq 3 is true.

Since, both equation satisfies the condition, the coordinate (0,3) is a solution.

Hence, Option D is the correct answer.

4 0
3 years ago
Is (0,0) a solution to this system?
Anuta_ua [19.1K]

Answer:

option-B

Step-by-step explanation:

we are given system of inequality as

y\leq x^2-4

y>2x-1

now, we can check solution

At (0,0):

we can plug x=0 and y=0

and check inequality

0\leq 0^2-4

0\leq -4

so, this is FALSE

now, we can check second inequality

0>2\times 0-1

0>-1

So, this is TRUE

so, option-B

5 0
3 years ago
Read 2 more answers
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