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REY [17]
2 years ago
15

Where are white blood cells produced? Olymph nodes O bone marrow O spleen 0 tonsils

Biology
2 answers:
lorasvet [3.4K]2 years ago
4 0
White blood cells are produced in bone marrow
ELEN [110]2 years ago
3 0

Answer:

all white cells are produced within the bone marrow

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If a branch is cut from a tree ,after some hours the stem remains firm explain<br> ?
hjlf

Answer:

The leaves no longer have water, which means that there is little osmotic pressure which keeps it turgid.

Explanation:

The stem still contains water because of the capillary action that occurs. However, since there is no strong attraction, the water cannot be pulled to the leaves.

4 0
2 years ago
Write the complementary DNA strand for the strand below TTAAGCGCTAATCGTACT
NISA [10]
AATTCGCGATTAGCATGA

The complementary strand it what matches to the original. T means the complementary letter will be A (and vise versa), C means the complementary letter will be G (and vise versa).
Hope this helps
5 0
2 years ago
which enzyme is responsible for facilitating the hydrogen bonding between nucleotides in a new DNA molecule
RideAnS [48]
The enzyme responsible for facilitating hydrogen bonding between nucleotides in a new DNA molecule is Polymerase.
8 0
2 years ago
Read 2 more answers
What term refers to cell division in eukaryotic cells?
Grace [21]

Answer:

Mitosis

Explanation:

Mitosis is a process of nuclear division in eukaryotic cells that occurs when a parent cell divides to produce two identical daughter cells

7 0
3 years ago
In Drosophila, vestigial (partially formed) wings (vg) are recessive to normal long wings (vg+) and the gene for this trait is a
Marina CMI [18]

Answer/ Explanation:

a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY

The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all  have normal length wings, the males will have white eyes and the females will have red eyes.

b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr

, Vg+Y

, VgXr

, VgY

. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.

c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye

Download docx
7 0
3 years ago
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