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qwelly [4]
3 years ago
9

Plan an experiment to measure the ideal mechanical advantage of a three-hole punch. (a) What materials would you need? (b) What

procedure would you use?
Physics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

A) Three hole punch and either a layered plastic or paper

B) Identify the lengths involved  ,

  Length of input arm / length of output arm = L1/ L2

Explanation:

<u>a) Materials involved includes :</u>

Three hole punch and either a layered plastic or paper

Identify the forces acting on the three-hole punch which are Input and output forces

Identify the points where they act

<u>B) procedures involved </u>

The mechanical advantage = output force / input force

step one:  Identify the lengths involved

assuming no friction or relatively small friction \

mechanical advantage can be calculated as : Length of input arm / length of output arm = L1/ L2

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When spiking a volleyball, a player changes the velocity of the ball from 4.2m/s to -24m/s along a certain direction. If the imp
dedylja [7]

Answer:

The mass of the volleyball is 0.32 kg.

Explanation:

Given that,

Initial speed of the ball, u = 4.2 m/s

Final speed of the ball, v = -24 m/s

The impulse delivered to the ball by the player is -9.3 kg-m/s.

To find,

Mass of the volleyball.

Solution,

The change in momentum of the volleyball is equal to the impulse delivered to the ball. It is given by :

J=m(v-u)

m=\dfrac{J}{(v-u)}

m=\dfrac{-9.3\ kg-m/s}{(-24-4.2)\ m/s}

m = 0.32 kg

So, the mass of the volleyball is 0.32 kg.

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3 years ago
A 1700kg rhino charges at a speed of 50.0km/h. What is the magnitude of the average force needed to bring the rhino to a stop in
Ksivusya [100]
Force (N) = mass (kg) x velocity (m/s) / time (s)
7 0
4 years ago
A blow dryer transfers thermal energy mainly by
AlekseyPX

Answer:

B

Explanation:

Through air

4 0
3 years ago
Read 2 more answers
A. A child is twirling a 1.52 kg object in a vertical circle with a radius of 67.6
steposvetlana [31]

Answer:

(a) 4.21 m/s

(b) 24.9 N

Explanation:

(a) Draw a free body diagram of the object when it is at the bottom of the circle.  There are two forces on the object: tension force T pulling up and weight force mg pulling down.

Sum the forces in the radial (+y) direction:

∑F = ma

T − mg = m v² / r

v = √(r (T − mg) / m)

v = √(0.676 m (54.7 N − 1.52 kg × 9.8 m/s²) / 1.52 kg)

v = 4.21 m/s

(b) Draw a free body diagram of the object when it is at the top of the circle.  There are two forces on the object: tension force T pulling down and weight force mg pulling down.

Sum the forces in the radial (-y) direction:

∑F = ma

T + mg = m v² / r

T = m v² / r − mg

T = (1.52 kg) (4.21 m/s)² / (0.676 m) −  (1.52 kg) (9.8 m/s²)

T = 24.9 N

6 0
3 years ago
A scuba diver, submerged under water looks up and seessunlight
maw [93]

Answer:

41.7975\ ^{\circ}

Explanation:

n_2 = Refraction index of water = 1.333

n_1 = Refraction index of air = 1

\theta_2 = Angle of sunlight = 30°

From Snell's law we have

\dfrac{n_1}{n_2}=\dfrac{sin\theta_2}{sin\theta_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{n_2sin\theta_2}{n_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{1.333sin30}{1}\\\Rightarrow \theta_1=41.7975\ ^{\circ}

The angle measured from the vertical does the sunlight strike thesurface of the water is 41.7975\ ^{\circ}

5 0
3 years ago
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