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Anna11 [10]
2 years ago
12

A 65 kg bungee jumper jumps off of a bridge. At an instant when they are 50 m above the ground, they are falling at a speed of 4

0 m/s, and the elastic in their bungee cord
(k = 650 N / m) is stretched by a distance of 2.0 m. What is the total mechanical energy of the bungee jumper at this instant ?
a. 1300 J
b. 52000 J
c. 31850 J
d. 85150 J
Physics
2 answers:
enot [183]2 years ago
8 0
The answer is 1 because u just did this test
maw [93]2 years ago
3 0

Answer:

the mechanical energy = a 1300J

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Are you sure you weren't given any options? Basically the electrical components, e.g wires and bulbs will be conductors, and the part comprising the outer casing, e.g plastic, glass, will be insulators
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3 years ago
A man climbs on to a wall that is 3.6m high and gains 2268J of potential energy. What is the mass of the man? *
Ilia_Sergeevich [38]
The mass of the man is 63 kilograms
There is it written down properly. Its hard to type this stuff in here

3 0
3 years ago
Brainliest please help<br><br>tell me if am right <br>if not correct me <br><br><br>​please
REY [17]

Answer:

See the answers below

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

<u>First case</u>

Vf = 6 [m/s]

Vo = 2 [m/s]

t = 2 [s]

6=2+a*2\\4=2*a\\a=2[m/s^{2} ]

<u>Second case</u>

Vf = 25 [m/s]

Vo = 5 [m/s]

a = 2 [m/s²]

25=5+2*t\\t = 10 [s]

<u>Third case</u>

Vo =4 [m/s]

a = 10 [m/s²]

t = 2 [s]

v_{f}=4+10*2\\v_{f}=24 [m/s]

<u>Fourth Case</u>

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

v_{f}=5+8*10\\v_{f}=85 [m/s]

<u>Fifth case</u>

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

8=v_{o}+4*2\\v_{0}=8-8\\v_{o}=0

8 0
3 years ago
Which of the following is correct for speed?
Olin [163]

Answer:

Speed is a "scalar" quantity

(C) is the correct answer

An object could travel at 10 m/s to some point and then return to the origin at 10 m/s for an average speed of 10 m/s, however it's displacement over that time would be zero for a net velocity of zero.

4 0
2 years ago
Solve the problems.
faltersainse [42]

Answer:

v= 1.911×10^8m/s

Explanation:

n=c/v

v=c/n

v= 3.0×10^8/1.57

v= 1.911×10^8m/s

7 0
2 years ago
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