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igor_vitrenko [27]
4 years ago
13

A 30 N block is being pulled along a horizontal surface with an acceleration of 6 m/s2 by a rope. The coefficient of kinetic fri

ction between the block and the surface is 0.5. What is the force applied by the rope?
Physics
1 answer:
nata0808 [166]4 years ago
6 0

Answer:

33N

Explanation:

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You stand on a merry-go-round which is spinning at f = 0.25 revolutions per second. You are R = 200 cm from the center. (a) Find
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Answer:

a) ω = 9.86 rad/s

b) ac = 194. 4 m/s²

c) minimum coefficient of static friction, µs = 19.8

Explanation:

a) angular speed, ω = 2πf, where f is frequency of revolution

1 rps = 6.283 rad/s, π = 3.142

ω = 2 * 3.14 * 0.25 * 6.28

ω = 9.86 rad/s

b) centripetal acceleration, a = rω²

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a = 2 * 9.86²

a = 194. 4 m/s²

c) µs = frictional force/ normal force

frictional force = centripetal force = ma; where a is centripetal acceleration

normal force = mg; where g = 9.8 m/s²

µs = ma/mg = a/g

µs = 194.4 ms⁻²/9.8 ms⁻²

c) minimum coefficient of static friction, µs = 19.8

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A heliocentric system is a sun-centered 
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Answer:

100

Explanation:

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