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igor_vitrenko [27]
3 years ago
13

A 30 N block is being pulled along a horizontal surface with an acceleration of 6 m/s2 by a rope. The coefficient of kinetic fri

ction between the block and the surface is 0.5. What is the force applied by the rope?
Physics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

33N

Explanation:

Download pdf
You might be interested in
A metal ball rolls from rest at Point A down the track to Point E as shown below.
Tju [1.3M]

Answer:

Explanation:

Velocity is at its greatest when kinetic energy is at its max which is when all the ball's energy has been transformed from potential energy to kinetic energy which is at the lowest point in its travels (assuming the ball is rolling down a ramp). You have no picture here so this answer is a general one, not a specific one.

8 0
2 years ago
What must the charge (sign and magnitude) of a 3.45 g particle be for it to remain stationary when placed in a downward-directed
Pani-rosa [81]

     charge must be equal to 5.74 ×10⁻⁵

 In the question it is said that the particle remains stationary which means the the net force on the particle is zero. So, the counterbalancing forces must be equal which means weight is equal to upward electric force.

     →    Fnet =0

     →    mg =  qE

 substituting the values we get :

         0.00345 × 9.81 =  q × 590

   →       q = 5.74 ×10⁻⁵

    Hence the charge must be equal to   5.74 ×10⁻⁵.

   Learn more about charges here:

          brainly.com/question/26092261

                    # SPJ4

8 0
1 year ago
Why does a truck that is traveling in the opposite direction to you on the street appear to be moving faster than it would if yo
svet-max [94.6K]
Hmmm...maybe it would be because since you're staying still then things appear to go by quickly.
5 0
3 years ago
The stoplights on a street are designed to keep traffic moving at 26 mi/h. the average length of a street block between traffic ligh
bonufazy [111]

We use the formula,

v = \frac{d}{t}.

Here, v is velocity and its value given 26 mi/h ( in m/s,  \frac{26 \times 1.609 \times 10^{3} m}{60 \times 60 s} =11.62 \ m/s ) and d is distance and its value is given 80 m.

Substituting these values in above formula we get,

t = \frac{80 m}{11.62m/s } = 6.88 \ s

Thus, the time delay between green lights on successive blocks to keep the traffic moving continuously is 6.88 s


3 0
2 years ago
Please answer any of these thanks !
KIM [24]
1).  The equation is: (speed) = (frequency) x (wavelength)

Speed = (256 Hz) x (1.3 m) = 332.8 meters per second

 2).  If the instrument is played louder, the amplitude of the waves increases.
On the oscilloscope, they would appear larger from top to bottom, but the
horizontal size of each wave doesn't change.

If the instrument is played at a higher pitch, then the waves become shorter,
because 'pitch' is directly related to the frequency of the waves, and higher
pitch means higher frequency and more waves in any period of time.

If the instrument plays louder and at higher pitch, the waves on the scope
become taller and there are more of them across the screen.

3).  The equation is:  Frequency = (speed) / (wavelength)
(Notice that this is exactly the same as the equation up above in question #1,
only with each side of that one divided by 'wavelength'.)

Frequency = 300,000,000 meters per second / 1,500 meters = 200,000 per second.

That's ' 200 k Hz ' .

Note:
I didn't think anybody broadcasts at 200 kHz, so I looked up BBC Radio 4
on-line, and I was surprised.  They broadcast on several different frequencies,
and one of them is 198 kHz !
7 0
3 years ago
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