The angular frequency of this motion is 5.46 rad/s.
The oscillation of spring is an example of Simple Harmonic Motion(SHM).
The general equation of an SHM is given by the formula.
X = Acos(wt)
Here A is the amplitude
ω is the angular frequency
T is the time
Comparing the above equation with the given condition,
X = 17.4 cm cos(5.46t)
A = 17.4 cm
ω = 5.46 rad/s
T = 1 s
Hence, the angular frequency of this motion is 5.46 rad/s.
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Answer:
<em>12.5watts</em>
Explanation:
Power = Workdone/Time
Since workdone = Force * Distance
Power = Force *distance/Time
Given
Force = 150N
Distance = 10m
Time = 2 minutes = 120seconds
Required
Power
Substitute the given values into the formula;
Power = 150 * 10/120
Power = 1500/120
Power = 12.5Watts
Hence his power is 12.5watts
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I’m not sure if its correct but I think it’s focal Ray point
For concave mirrors, some generalizations can be made to simplify ray construction. They are: An incident ray traveling parallel to the principal axis will reflect and pass through the focal point. An incident ray traveling through the focal point will reflect and travel parallel to the principal axis.
A spring scale measures weight because <span>It works by Hooke's Law, which states that the force needed to extend a </span>spring<span> is proportional to the distance that </span>spring<span> is extended from its rest position. Therefore, the </span>scale<span> markings on the </span>spring<span> balance are equally spaced. A </span>spring scale<span> can</span>not measure mass<span>, only </span>weight<span>. hope that helped</span>
Answer:
The momentum of block B = 27 Kg m/s
Explanation:
Given,
The initial momentum of block A, MU = 15 Kg m/s
The final momentum of block A, MV = -12 Kg m/s
Consider the block B is initially at rest.
Therefore, the initial momentum of block B, mu = 0
According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.
<em> MU + mu = MV + mv</em>
15 + (0) = (-12) + mv
mv = 15 + 12
= 27 Kg m/s
Hence, the momentum of the block B after impact is, mv = 27 Kg m/s
