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frosja888 [35]
4 years ago
7

When doing scientific research, the sources used should be

Physics
1 answer:
VMariaS [17]4 years ago
4 0
The answer is: RELIABLE
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A kitten has a mass of 0.8 kg. It is moving forward with a momentum of 0.5 kg • m/s. What is the kitten’s velocity?
morpeh [17]

The kitten's velocity is   V=0.625 m/s

<u>Explanation:</u>

<u>Solving the problem,</u>

Given

Mass=0.8 kg

Momentum=0.5 kg.m/s

Velocity=?

We have the formula,

P=M*V

V=P/M

V=0.5 kg.m/s/0.8 kg

V=0.625 m/s

The kitten's velocity is   V=0.625 m/s

<u />

5 0
4 years ago
Si olvidas un trozo de chocolate cerca de la estufa encendida, al rato, observa tu chocolate derretido, ¿Cómo estarán las partíc
eduard

Answer:

partículas estarían separadas

Explanation:

ya que con el calor las partículas se alborotan y con frío se congelan

4 0
3 years ago
A 3.0 kg ball is lifted two meters upward in two seconds, and a 6.0 kg ball is lifted one meter upward in one second? Which requ
Sav [38]

Answer:

1. They both uses same energy

2. The 6 kg ball requires more power than 3kg ball

Explanation:

Sample 1

m = 3kg

g= 10m/s^2

h = 2m

t = 2secs

W = mgh = 3 x 10 x 2 = 60J

P= w/t = 60/2 = 30watts

Sample 2

m = 6kg

g= 10m/s^2

h = 1m

t = 1sec

W = mgh = 6 x 10 x 1 = 60J

P= w/t = 60/1 = 60watts

They both uses same energy but different power. The 6 kg ball requires more power than 3kg ball

3 0
4 years ago
A 1000kg roller coaster begins at 10m tall hill with initial velocity of 6m/s and travels down until a second hill. 1700J is tra
nadezda [96]

Answer:

The maximum height could be 10.6 meters.

Explanation:

For this kind of exercise, we use the general principle for conservation of mechanical energy (E) that states:

E_1+W_f=E_2 (1)

That means the mechanical energy an object has on a point 2 should be equal to the mechanical energy on a point 1 plus the energy transformed into heat due friction denoted as Wf (It is negative because is lost). In our case point 1 is the point where the roller coaster begins and point 2 is at the second hill. Tola mechanical energy is the sum of potential gravitational energy and kinetic energy, so (1) is :

K_{1}+U_{1}+W_{f}=K_{2}+U_{2}

with K the kinetic energy and U the potential energy, remember potential energy is mgh and kinetic energy is \frac{mv^2}{2} with m the mass, v the velocity and h the height, then:

\frac{mv_1^2}{2}+mgh_1+W_{f}=\frac{mv_2^2}{2}+mgh_2

Solving for h_2:

h_2=\frac{\frac{mv_1^2}{2}+mgh_1+W_{f}-\frac{mv_2^2}{2}}{mg}=\frac{\frac{(1000)(6)^2}{2}+(1000)(9.8)(10)-1700-\frac{(1000)(4.6)^2}{2}}{(1000)(9.81)}

h_2=10.6 m

4 0
4 years ago
Baseball scouts often use a radar gun to measure the speed of a pitch. One particular model of radar gun emits a microwave signa
kkurt [141]

Answer:

What will be the increase in frequency if these waves are reflected = 2979.63Hz

Explanation:

The detailed steps and appropriate formula is as shown in the attached file.

4 0
3 years ago
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