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Zinaida [17]
3 years ago
10

Evaluate the following expression when x = 3 and y = 4: 2x + y2 - 1

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0

Answer:

21

Step-by-step explanation:

x = 3

y = 4

2x + y² - 1

2(3) + 4² - 1

2(3) + 16 - 1

6 + 16 - 1

22 - 1

21

Elena L [17]3 years ago
3 0
<h2>Never Mind heh :)))))))))))))))</h2>
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Step-by-step explanation:

f(x) = x² + x + 3/4

in general, such a quadratic function is defined as

f(x) = a×x² + b×x + c

the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 1

c = 3/4

x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =

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remember, i = sqrt(-1)

f(x) has no 0 results for x = real numbers.

for the solution we need to use imaginary numbers.

6 0
3 years ago
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Answer:

3600000

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3 years ago
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Step-by-step explanation:

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