Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
Step-by-step explanation:
Use the basic simple interest formula:
P * r * t = I and put the info into a table with those variables along the top, formig the columns we need:
P * r * t = I
Acct 1
Acct 2
If we have a total of 1500 to split up between 2 accounts, we put x amount of money into one and then have 1500-x left to put into the other. We will fill those in along with the interest rates in decimal form and the time of 1 year:
P * r * t = I
Acct 1 x .04 1
Acct 2 1500-x .05 1
Looking at the formula we are told that Prt = I, so we will multiply P times r times t and fill in the I column:
P * r * t - I
Acct 1 x .04 1 .04x
Acct 2 1500-x .05 1 .05(1500-x)
The total Interest earned by the addition of the interest earned from both accounts is 69.50. So we add the interest column together and set it equal to 69.50:
.04x + .05(1500 - x) = 69.50 and
.04x + 75 - .05x = 69.50 and
-.01x = -5.5 so
x = 550
That's how much money is in the account earning 4% interest.
Answer:
10 km
Step-by-step explanation:
volume of cube = s^3
1 m = 100 cm
volume = s^3 = (1 m)^3 = (100 cm)^3 = 1,000,000 cm^3
Since 1 m^3 = 1,000,000 cm^3, when you lay down the 1-cm cubes in a straight line with the edges touching, the line is 1,000,000 cm long.
1,000,000 cm = 10,000 m = 10 km
Answer:
2x2+17x+28/x+6
Step-by-step explanation:
